Array Reversal in C – Hacker Rank Solution | HackerRank Programming Solutions | HackerRank C Solutions

Hello Programmers/Coders, Today we are going to share solutions of Programming problems of HackerRank of Programming Language C . At Each Problem with Successful submission with all Test Cases Passed, you will get an score or marks. And after solving maximum problems, you will be getting stars. This will highlight you profile to the recruiters.

In this post, you will find the solution for Array Reversal in C-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.

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C is one of the most widely used Programming Languages. it is basically used to build Operating System. C was developed by Dennis Ritchie in 1972. Below are some examples of C Programming which might you understanding the basics of C Programming.


Given an array, of size n, reverse it.
Example: If array, arr = [1,2,3,4,5], after reversing it, the array should be, arr[5,4,3,2,1].


Input Format :

The first line contains an integer, n, denoting the size of the array. The next line contains n space-separated integers denoting the elements of the array.

Constraints :

  • 1<=n<=1000
  • 1<=arri<=1000, where arri is the ith element of the array.

Output Format :

The output is handled by the code given in the editor, which would print the array.

Sample Input 0


16 13 7 2 1 12

Sample Output 0

12 1 2 7 13 16 

Explanation 0

Given array, arr = [16,13,7,2,1,12]. After reversing the array, arr = [12,1,2,7,13,16]

Sample Input 1


1 13 15 20 12 13 2 

Sample Output 1

2 13 12 20 15 13 1 

Sample Input 2


15 5 16 15 17 11 5 11 

Sample Output 2

11 5 11 17 15 16 5 15 
Array Reversal in C – Hacker Rank Solution
#include <stdio.h>
#include <stdlib.h>

int main()
    int num, *arr,*arr2,i;
    scanf("%d", &num);
    arr = (int*) malloc(num * sizeof(int));
    for(i = 0; i < num; i++) {
        scanf("%d", arr + i);
    arr2 = (int*) malloc(num * sizeof(int));
        arr2[i-1] = arr[num-i];
    for(i = 0; i < num; i++)
        printf("%d ", *(arr2 + i));
    return 0;

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