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Hello **Programmers/Coders,** Today we are going to share ** solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python**. At Each Problem with Successful submission with

**all Test Cases Passed,**you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the **Balanced Binary Tree** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either *Easy*, *Medium*, or *Hard*.

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- Mathematics/Basic Logical Based Questions
- Arrays
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- Stack & Queue
- Trees & Graphs
- Greedy Algorithms
- Breadth-First Search
- Depth-First Search
- Sorting & Searching
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- Database
- Linked List
- Recursion, etc.

Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

** Link for the Problem** – Balanced Binary Tree– LeetCode Problem

Balanced Binary Tree– LeetCode Problem

**Problem:**

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as:

a binary tree in which the left and right subtrees of

everynode differ in height by no more than 1.

**Example 1:**

Input:root = [3,9,20,null,null,15,7]Output:true

**Example 2:**

Input:root = [1,2,2,3,3,null,null,4,4]Output:false

**Example 3:**

Input:root = []Output:true

**Constraints:**

- The number of nodes in the tree is in the range
`[0, 5000]`

. `-10`

^{4}<= Node.val <= 10^{4}

Balanced Binary Tree– LeetCode Solutions

Balanced Binary Tree Solution in C++:

class Solution { public: bool isBalanced(TreeNode* root) { return maxDepth(root) != -1; } private: // return height of root if balanced; otherwise, return -1 int maxDepth(TreeNode* root) { if (!root) return 0; const int leftHeight = maxDepth(root->left); if (leftHeight == -1) return -1; const int rightHeight = maxDepth(root->right); if (rightHeight == -1) return -1; if (abs(leftHeight - rightHeight) > 1) return -1; return 1 + max(leftHeight, rightHeight); } };

Balanced Binary Tree Solution in Java:

class Solution { public boolean isBalanced(TreeNode root) { return maxDepth(root) != -1; } // return height of root if balanced; otherwise, return -1 private int maxDepth(TreeNode root) { if (root == null) return 0; final int leftHeight = maxDepth(root.left); if (leftHeight == -1) return -1; final int rightHeight = maxDepth(root.right); if (rightHeight == -1) return -1; if (Math.abs(leftHeight - rightHeight) > 1) return -1; return 1 + Math.max(leftHeight, rightHeight); } }

Balanced Binary Tree Solution in Python:

class Solution: def isBalanced(self, root: Optional[TreeNode]) -> bool: if not root: return True def maxDepth(root: Optional[TreeNode]) -> int: if not root: return 0 return 1 + max(maxDepth(root.left), maxDepth(root.right)) return abs(maxDepth(root.left) - maxDepth(root.right)) <= 1 and \ self.isBalanced(root.left) and self.isBalanced(root.right)

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