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In this post, you will find the solution for the **Balanced Binary Tree** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Balanced Binary Tree– LeetCode Problem

Balanced Binary Tree– LeetCode Problem

**Problem:**

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as:

a binary tree in which the left and right subtrees of

everynode differ in height by no more than 1.

**Example 1:**

Input:root = [3,9,20,null,null,15,7]Output:true

**Example 2:**

Input:root = [1,2,2,3,3,null,null,4,4]Output:false

**Example 3:**

Input:root = []Output:true

**Constraints:**

- The number of nodes in the tree is in the range
`[0, 5000]`

. `-10`

^{4}<= Node.val <= 10^{4}

Balanced Binary Tree– LeetCode Solutions

Balanced Binary Tree Solution in C++:

class Solution { public: bool isBalanced(TreeNode* root) { return maxDepth(root) != -1; } private: // return height of root if balanced; otherwise, return -1 int maxDepth(TreeNode* root) { if (!root) return 0; const int leftHeight = maxDepth(root->left); if (leftHeight == -1) return -1; const int rightHeight = maxDepth(root->right); if (rightHeight == -1) return -1; if (abs(leftHeight - rightHeight) > 1) return -1; return 1 + max(leftHeight, rightHeight); } };

Balanced Binary Tree Solution in Java:

class Solution { public boolean isBalanced(TreeNode root) { return maxDepth(root) != -1; } // return height of root if balanced; otherwise, return -1 private int maxDepth(TreeNode root) { if (root == null) return 0; final int leftHeight = maxDepth(root.left); if (leftHeight == -1) return -1; final int rightHeight = maxDepth(root.right); if (rightHeight == -1) return -1; if (Math.abs(leftHeight - rightHeight) > 1) return -1; return 1 + Math.max(leftHeight, rightHeight); } }

Balanced Binary Tree Solution in Python:

class Solution: def isBalanced(self, root: Optional[TreeNode]) -> bool: if not root: return True def maxDepth(root: Optional[TreeNode]) -> int: if not root: return 0 return 1 + max(maxDepth(root.left), maxDepth(root.right)) return abs(maxDepth(root.left) - maxDepth(root.right)) <= 1 and \ self.isBalanced(root.left) and self.isBalanced(root.right)