Boxes through a Tunnel in C – Hacker Rank Solution| HackerRank Programming Solutions | HackerRank C Solutions

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C is one of the most widely used Programming Languages. it is basically used to build Operating System. C was developed by Dennis Ritchie in 1972. Below are some examples of C Programming which might you understanding the basics of C Programming.


You are transporting some boxes through a tunnel, where each box is a parallelepiped, and is characterized by its length, width and height.The height of the tunnel 41 feet and the width can be assumed to be infinite. A box can be carried through the tunnel only if its height is strictly less than the tunnel’s height. Find the volume of each box that can be successfully transported to the other end of the tunnel. Note: Boxes cannot be rotated. 

Input Format

The first line contains a single integer n, denoting the number of boxes.n lines follow with three integers on each separated by single spaces – lengthiwidthi and heighti which are length, width and height in feet of the i-th box.


  • 1<=n<=100
  • 1<=lengthi,heighti,widthi<=100 

Output Format

For every box from the input which has a height lesser than 41 feet, print its volume in a separate line.

Sample Input 0

5 5 5
1 2 40
10 5 41
7 2 42

Sample Output 0


Explanation 0

The first box is really low, only feet tall, so it can pass through the tunnel and its volume is 5 * 5 * 5 = 125The second box is sufficiently low, its volume is 1 * 2 * 40 = 80The third box is exactly 41 feet tall, so it cannot pass. The same can be said about the fourth box.

Boxes through a Tunnel C – Hacker Rank Solution
#include <stdio.h>
#include <stdlib.h>
#define MAX_HEIGHT 41

struct box
 * Define three fields of type int: length, width and height
 int length;
 int width;
 int height;

typedef struct box box;

int get_volume(box b) {
 * Return the volume of the box
 return (b.length*b.width*b.height);

int is_lower_than_max_height(box b) {
 * Return 1 if the box's height is lower than MAX_HEIGHT and 0 otherwise
    if(b.height > 40)
  return 0;
  return 1;

int main()
 int n;
 scanf("%d", &n);
 box *boxes = malloc(n * sizeof(box));
 for (int i = 0; i < n; i++) {
  scanf("%d%d%d", &boxes[i].length, &boxes[i].width, &boxes[i].height);
 for (int i = 0; i < n; i++) {
  if (is_lower_than_max_height(boxes[i])) {
   printf("%d\n", get_volume(boxes[i]));
 return 0;

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