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Hello **Programmers/Coders,** Today we are going to share ** solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python**. At Each Problem with Successful submission with

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In this post, you will find the solution for the **Candy** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Candy– LeetCode Problem

Candy– LeetCode Problem

**Problem:**

There are `n`

children standing in a line. Each child is assigned a rating value given in the integer array `ratings`

.

You are giving candies to these children subjected to the following requirements:

- Each child must have at least one candy.
- Children with a higher rating get more candies than their neighbors.

Return *the minimum number of candies you need to have to distribute the candies to the children*.

**Example 1:**

Input:ratings = [1,0,2]Output:5Explanation:You can allocate to the first, second and third child with 2, 1, 2 candies respectively.

**Example 2:**

Input:ratings = [1,2,2]Output:4Explanation:You can allocate to the first, second and third child with 1, 2, 1 candies respectively. The third child gets 1 candy because it satisfies the above two conditions.

**Constraints:**

`n == ratings.length`

`1 <= n <= 2 * 10`

^{4}`0 <= ratings[i] <= 2 * 10`

^{4}

Candy– LeetCode Solutions

Candy Solution in C++:

class Solution { public: int candy(vector<int>& ratings) { const int n = ratings.size(); int ans = 0; vector<int> l(n, 1); vector<int> r(n, 1); for (int i = 1; i < n; ++i) if (ratings[i] > ratings[i - 1]) l[i] = l[i - 1] + 1; for (int i = n - 2; i >= 0; --i) if (ratings[i] > ratings[i + 1]) r[i] = r[i + 1] + 1; for (int i = 0; i < n; ++i) ans += max(l[i], r[i]); return ans; } };

Candy Solution in Java:

class Solution { public int candy(int[] ratings) { final int n = ratings.length; int ans = 0; int[] l = new int[n]; int[] r = new int[n]; Arrays.fill(l, 1); Arrays.fill(r, 1); for (int i = 1; i < n; ++i) if (ratings[i] > ratings[i - 1]) l[i] = l[i - 1] + 1; for (int i = n - 2; i >= 0; --i) if (ratings[i] > ratings[i + 1]) r[i] = r[i + 1] + 1; for (int i = 0; i < n; ++i) ans += Math.max(l[i], r[i]); return ans; } }

Candy Solution in Python:

class Solution: def candy(self, ratings: List[int]) -> int: n = len(ratings) ans = 0 l = [1] * n r = [1] * n for i in range(1, n): if ratings[i] > ratings[i - 1]: l[i] = l[i - 1] + 1 for i in range(n - 2, -1, -1): if ratings[i] > ratings[i + 1]: r[i] = r[i + 1] + 1 for a, b in zip(l, r): ans += max(a, b) return ans