Combine Two Tables LeetCode Programming Solutions 2022 | LeetCode Problem Solutions in SQL [💯Correct]

Combine Two Tables LeetCode Solution | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Solutions in SQL

Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Combine Two Tables in SQL(Structured Query Language)-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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About LeetCode

LeetCode is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews. 

LeetCode is for software engineers who are looking to practice technical questions and advance their skills. Mastering the questions in each level on LeetCode is a good way to prepare for technical interviews and keep your skills sharp. They also have a repository of solutions with the reasoning behind each step.

LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either EasyMedium, or Hard.

LeetCode problems focus on algorithms and data structures. Here is some topic you can find problems on LeetCode:

  • Mathematics/Basic Logical Based Questions
  • Arrays
  • Strings
  • Hash Table
  • Dynamic Programming
  • Stack & Queue
  • Trees & Graphs
  • Greedy Algorithms
  • Breadth-First Search
  • Depth-First Search
  • Sorting & Searching
  • BST (Binary Search Tree)
  • Database
  • Linked List
  • Recursion, etc.

Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the ProblemCombine Two Tables– LeetCode Problem

Combine Two Tables– LeetCode Problem


Table: Person

| Column Name | Type    |
| personId    | int     |
| lastName    | varchar |
| firstName   | varchar |
personId is the primary key column for this table.
This table contains information about the ID of some persons and their first and last names.

Table: Address

| Column Name | Type    |
| addressId   | int     |
| personId    | int     |
| city        | varchar |
| state       | varchar |
addressId is the primary key column for this table.
Each row of this table contains information about the city and state of one person with ID = PersonId.

Write an SQL query to report the first name, last name, city, and state of each person in the Person table. If the address of a personId is not present in the Address table, report null instead.

Return the result table in any order.

The query result format is in the following example.

Example 1:

Person table:
| personId | lastName | firstName |
| 1        | Wang     | Allen     |
| 2        | Alice    | Bob       |
Address table:
| addressId | personId | city          | state      |
| 1         | 2        | New York City | New York   |
| 2         | 3        | Leetcode      | California |
| firstName | lastName | city          | state    |
| Allen     | Wang     | Null          | Null     |
| Bob       | Alice    | New York City | New York |
There is no address in the address table for the personId = 1 so we return null in their city and state.
addressId = 1 contains information about the address of personId = 2.
Combine Two Tables– LeetCode Solutions
Combine Two Tables Solution :
SELECT FirstName, LastName, City, State
FROM Person
ON Person.PersonId = Address.PersonId;

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