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** Link for the Problem** – Convert Sorted Array to Binary Search Tree– LeetCode Problem

Convert Sorted Array to Binary Search Tree– LeetCode Problem

**Problem:**

Given an integer array `nums`

where the elements are sorted in **ascending order**, convert *it to a height-balanced binary search tree*.

A **height-balanced** binary tree is a binary tree in which the depth of the two subtrees of every node never differs by more than one.

**Example 1:**

Input:nums = [-10,-3,0,5,9]Output:[0,-3,9,-10,null,5]Explanation:[0,-10,5,null,-3,null,9] is also accepted:

**Example 2:**

Input:nums = [1,3]Output:[3,1]Explanation:[1,3] and [3,1] are both a height-balanced BSTs.

**Constraints:**

`1 <= nums.length <= 10`

^{4}`-10`

^{4}<= nums[i] <= 10^{4}`nums`

is sorted in a**strictly increasing**order.

Convert Sorted Array to Binary Search Tree– LeetCode Solutions

Convert Sorted Array to Binary Search Tree Solution in C++:

class Solution { public: TreeNode* sortedArrayToBST(vector<int>& nums) { return helper(nums, 0, nums.size() - 1); } private: TreeNode* helper(vector<int>& nums, int l, int r) { if (l > r) return nullptr; const int m = l + (r - l) / 2; TreeNode* root = new TreeNode(nums[m]); root->left = helper(nums, l, m - 1); root->right = helper(nums, m + 1, r); return root; } };

Convert Sorted Array to Binary Search Tree Solution in Java:

class Solution { public TreeNode sortedArrayToBST(int[] nums) { return helper(nums, 0, nums.length - 1); } private TreeNode helper(int nums[], int l, int r) { if (l > r) return null; final int m = l + (r - l) / 2; TreeNode root = new TreeNode(nums[m]); root.left = helper(nums, l, m - 1); root.right = helper(nums, m + 1, r); return root; } }

Convert Sorted Array to Binary Search Tree Solution in Python:

class Solution: def sortedArrayToBST(self, nums: List[int]) -> TreeNode: def helper(l: int, r: int) -> TreeNode: if l > r: return None m = (l + r) // 2 root = TreeNode(nums[m]) root.left = helper(l, m - 1) root.right = helper(m + 1, r) return root return helper(0, len(nums) - 1)