Copy List with Random Pointer LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Copy List with Random Pointer in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the ProblemCopy List with Random Pointer– LeetCode Problem

Copy List with Random Pointer– LeetCode Problem

Problem:

A linked list of length n is given such that each node contains an additional random pointer, which could point to any node in the list, or null.

Construct a deep copy of the list. The deep copy should consist of exactly n brand new nodes, where each new node has its value set to the value of its corresponding original node. Both the next and random pointer of the new nodes should point to new nodes in the copied list such that the pointers in the original list and copied list represent the same list state. None of the pointers in the new list should point to nodes in the original list.

For example, if there are two nodes X and Y in the original list, where X.random --> Y, then for the corresponding two nodes x and y in the copied list, x.random --> y.

Return the head of the copied linked list.

The linked list is represented in the input/output as a list of n nodes. Each node is represented as a pair of [val, random_index] where:

  • val: an integer representing Node.val
  • random_index: the index of the node (range from 0 to n-1) that the random pointer points to, or null if it does not point to any node.

Your code will only be given the head of the original linked list.

Example 1:

e1
Input: head = [[7,null],[13,0],[11,4],[10,2],[1,0]]
Output: [[7,null],[13,0],[11,4],[10,2],[1,0]]

Example 2:

e2
Input: head = [[1,1],[2,1]]
Output: [[1,1],[2,1]]

Example 3:

e3
Input: head = [[3,null],[3,0],[3,null]]
Output: [[3,null],[3,0],[3,null]]

Constraints:

  • 0 <= n <= 1000
  • -104 <= Node.val <= 104
  • Node.random is null or is pointing to some node in the linked list.
Copy List with Random Pointer– LeetCode Solutions
Copy List with Random Pointer Solution in C++:
class Solution {
 public:
  Node* copyRandomList(Node* head) {
    if (!head)
      return nullptr;
    if (map.count(head))
      return map[head];

    Node* newNode = new Node(head->val);
    map[head] = newNode;

    newNode->next = copyRandomList(head->next);
    newNode->random = copyRandomList(head->random);

    return newNode;
  }

 private:
  unordered_map<Node*, Node*> map;
};
Copy List with Random Pointer Solution in Java:
class Solution {
  public Node copyRandomList(Node head) {
    if (head == null)
      return null;
    if (map.containsKey(head))
      return map.get(head);

    Node newNode = new Node(head.val);
    map.put(head, newNode);

    newNode.next = copyRandomList(head.next);
    newNode.random = copyRandomList(head.random);

    return newNode;
  }

  private Map<Node, Node> map = new HashMap<>();
}
Copy List with Random Pointer Solution in Python:
class Solution:
  def copyRandomList(self, head: 'Node') -> 'Node':
    if head is None:
      return None
    if head in self.dict:
      return self.dict[head]

    self.dict[head] = Node(head.val)
    self.dict[head].next = self.copyRandomList(head.next)
    self.dict[head].random = self.copyRandomList(head.random)

    return self.dict[head]

  dict = {}

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