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Link for the Problem – Day 29: Bitwise AND – Hacker Rank Solution
Day 29: Bitwise AND – Hacker Rank Solution
Problem:
Objective
Welcome to the last day! Today, we’re discussing bitwise operations. Check out the Tutorial tab for learning materials and an instructional video!
Task
Given set . Find two integers, and (where ), from set such that the value of is the maximum possible and also less than a given integer, . In this case, represents the bitwise AND operator.
Function Description
Complete the bitwiseAnd function in the editor below.
bitwiseAnd has the following paramter(s):
– int N: the maximum integer to consider
– int K: the limit of the result, inclusive
Returns
– int: the maximum value of within the limit.
Input Format
The first line contains an integer, , the number of test cases.
Each of the subsequent lines defines a test case as space-separated integers, and , respectively.
Constraints
Sample Input
STDIN Function ----- -------- 3 T = 3 5 2 N = 5, K = 2 8 5 N = 8, K = 5 2 2 N = 8, K = 5
Sample Output
1 4 0
Explanation
All possible values of and are:
The maximum possible value of that is also is , so we print on a new line.
Day 29: Bitwise AND – Hacker Rank Solution
import java.util.Scanner; /** * @author Techno-RJ * */ public class Day29BitwiseAND { public static void main(String[] args) { Scanner in = new Scanner(System.in); int t = in.nextInt(); for (int a0 = 0; a0 < t; a0++) { int n = in.nextInt(); int k = in.nextInt(); in.close(); if (((k - 1) | k) <= n) { System.out.println(k - 1); } else { System.out.println(k - 2); } } } }