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In this post, you will find the solution for **Day 29: Bitwise AND** **in Java-HackerRank Problem**. We are providing the **correct and tested solutions** of coding problems present on **HackerRank**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Day 29: Bitwise AND โ Hacker Rank Solution

Day 29: Bitwise AND โ Hacker Rank Solution

**Problem:**

**Objective**

Welcome to the last day! Today, we’re discussing bitwise operations. Check out the Tutorial tab for learning materials and an instructional video!

**Task**

Given set . Find two integers, and (where ), from set such that the value of is the maximum possible *and also less than a given integer, *. In this case, represents the *bitwise AND* operator.

**Function Description**

Complete the *bitwiseAnd* function in the editor below.

*bitwiseAnd* has the following paramter(s):

– *int N:* the maximum integer to consider

– *int K:* the limit of the result, inclusive

**Returns**

– *int:* the maximum value of within the limit.

**Input Format**

The first line contains an integer, , the number of test cases.

Each of the subsequent lines defines a test case as space-separated integers, and , respectively.

**Constraints**

**Sample Input**

STDIN Function ----- -------- 3 T = 3 5 2 N = 5, K = 2 8 5 N = 8, K = 5 2 2 N = 8, K = 5

**Sample Output**

1 4 0

**Explanation**

All possible values of and are:

The maximum possible value of that is also is , so we print on a new line.

Day 29: Bitwise AND โ Hacker Rank Solution

import java.util.Scanner; /** * @author Techno-RJ * */ public class Day29BitwiseAND { public static void main(String[] args) { Scanner in = new Scanner(System.in); int t = in.nextInt(); for (int a0 = 0; a0 < t; a0++) { int n = in.nextInt(); int k = in.nextInt(); in.close(); if (((k - 1) | k) <= n) { System.out.println(k - 1); } else { System.out.println(k - 2); } } } }

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