Day 3: Arrays in Javascript | 10 Days Of JavaScript Solutions | HackerRank Programming Solutions [💯Correct]

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Introduction To JavaScript

JavaScript is a lightweight, cross-platform, and interpreted scripting language. It is well-known for the development of web pages, many non-browser environments also use it. JavaScript can be used for Client-side developments as well as Server-side developments. JavaScript contains a standard library of objects, like Array, Date, and Math, and a core set of language elements like operators, control structures, and statements.

Advantages of JavaScript

The merits of using JavaScript are −

  • Less server interaction − You can validate user input before sending the page off to the server. This saves server traffic, which means less load on your server.
  • Immediate feedback to the visitors − They don’t have to wait for a page reload to see if they have forgotten to enter something.
  • Increased interactivity − You can create interfaces that react when the user hovers over them with a mouse or activates them via the keyboard.
  • Richer interfaces − You can use JavaScript to include such items as drag-and-drop components and sliders to give a Rich Interface to your site visitors.

Link for the ProblemDay 3: Arrays – Hacker Rank Solution

Day 3: Arrays – Hacker Rank Solution

Problem:

Objective

In this challenge, we learn about Arrays. Check out the attached tutorial for more details.

Function Description

Complete the getSecondLargest function in the editor below.

getSecondLargest has the following parameters:

  • int nums[n]: an array of integers

Returns

  • int: the second largest number in 

Input Format

image 18

Constraints

image 19

Sample Input 0

5
2 3 6 6 5

Sample Output 0

5

Explanation 0

image 20
Day 3: Arrays – Hacker Rank Solution
function getSecondLargest(nums) {
  let firstLargestNum = 0;
  let secondLargestNum = 0;

  for (let i = 0; i < nums.length; i++) {
    if (nums[i] > firstLargestNum) {
      secondLargestNum = firstLargestNum;
      firstLargestNum = nums[i];
    }
    if (nums[i] > secondLargestNum && nums[i] < firstLargestNum) {
      secondLargestNum = nums[i];
    }
  }
  return secondLargestNum;
}

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