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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.
In this post, you will find the solution for the Decode Ways in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.
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Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.
Link for the Problem – Decode Ways– LeetCode Problem
Decode Ways– LeetCode Problem
Problem:
A message containing letters from A-Z
can be encoded into numbers using the following mapping:
'A' -> "1" 'B' -> "2" ... 'Z' -> "26"
To decode an encoded message, all the digits must be grouped then mapped back into letters using the reverse of the mapping above (there may be multiple ways). For example, "11106"
can be mapped into:
"AAJF"
with the grouping(1 1 10 6)
"KJF"
with the grouping(11 10 6)
Note that the grouping (1 11 06)
is invalid because "06"
cannot be mapped into 'F'
since "6"
is different from "06"
.
Given a string s
containing only digits, return the number of ways to decode it.
The test cases are generated so that the answer fits in a 32-bit integer.
Example 1:
Input: s = "12" Output: 2 Explanation: "12" could be decoded as "AB" (1 2) or "L" (12).
Example 2:
Input: s = "226" Output: 3 Explanation: "226" could be decoded as "BZ" (2 26), "VF" (22 6), or "BBF" (2 2 6).
Example 3:
Input: s = "06" Output: 0 Explanation: "06" cannot be mapped to "F" because of the leading zero ("6" is different from "06").
Constraints:
1 <= s.length <= 100
s
contains only digits and may contain leading zero(s).
Decode Ways– LeetCode Solutions
Decode Ways Solution in C++:
class Solution { public: int numDecodings(string s) { const int n = s.length(); // dp[i] := # of ways to decode s[i..n) vector<int> dp(n + 1); dp[n] = 1; // "" dp[n - 1] = isValid(s[n - 1]); for (int i = n - 2; i >= 0; --i) { if (isValid(s[i])) dp[i] += dp[i + 1]; if (isValid(s[i], s[i + 1])) dp[i] += dp[i + 2]; } return dp[0]; } private: bool isValid(char c) { return c != '0'; } bool isValid(char c1, char c2) { return c1 == '1' || c1 == '2' && c2 < '7'; } };
Decode Ways Solution in Java:
class Solution { public int numDecodings(String s) { final int n = s.length(); // dp[i] := # of ways to decode s[i..n) int[] dp = new int[n + 1]; dp[n] = 1; // "" dp[n - 1] = isValid(s.charAt(n - 1)) ? 1 : 0; for (int i = n - 2; i >= 0; --i) { if (isValid(s.charAt(i))) dp[i] += dp[i + 1]; if (isValid(s.charAt(i), s.charAt(i + 1))) dp[i] += dp[i + 2]; } return dp[0]; } private boolean isValid(char c) { return c != '0'; } private boolean isValid(char c1, char c2) { return c1 == '1' || c1 == '2' && c2 < '7'; } }
Decode Ways Solution in Python:
class Solution: def numDecodings(self, s: str) -> int: n = len(s) # dp[i] := # of ways to decode s[i..n) dp = [0] * n + [1] def isValid(a: chr, b=None) -> bool: if b: return a == '1' or a == '2' and b < '7' return a != '0' if isValid(s[-1]): dp[n - 1] = 1 for i in range(n - 2, -1, -1): if isValid(s[i]): dp[i] += dp[i + 1] if isValid(s[i], s[i + 1]): dp[i] += dp[i + 2] return dp[0]
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