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Link for the Problem – Employees Earning More Than Their Managers– LeetCode Problem
Employees Earning More Than Their Managers– LeetCode Problem
+-------------+---------+ | Column Name | Type | +-------------+---------+ | id | int | | name | varchar | | salary | int | | managerId | int | +-------------+---------+ id is the primary key column for this table. Each row of this table indicates the ID of an employee, their name, salary, and the ID of their manager.
Write an SQL query to find the employees who earn more than their managers.
Return the result table in any order.
The query result format is in the following example.
Input: Employee table: +----+-------+--------+-----------+ | id | name | salary | managerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | Null | | 4 | Max | 90000 | Null | +----+-------+--------+-----------+ Output: +----------+ | Employee | +----------+ | Joe | +----------+ Explanation: Joe is the only employee who earns more than his manager.
Employees Earning More Than Their Managers– LeetCode Solutions
Employees Earning More Than Their Managers Solution in SQL:
# Write your MySQL query statement below select e1.Name as Employee from Employee e1, Employee e2 where e1.ManagerId = e2.Id and e1.Salary > e2.Salary