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In this post, you will find the solution for **Equal Stacks** **in Java-HackerRank Problem**. We are providing the **correct and tested solutions** of coding problems present on **HackerRank**. If you are not able to solve any problem, then you can take help from our Blog/website.

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**Introduction To Algorithm**

The word **Algorithm** means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results.

**Advantages of Algorithms:**

- It is easy to understand.
- Algorithm is a step-wise representation of a solution to a given problem.
- In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

** Link for the Problem** – Equal Stacks – Hacker Rank Solution

Equal Stacks– Hacker Rank Solution

**Problem:**

You have three stacks of cylinders where each cylinder has the same diameter, but they may vary in height. You can change the height of a stack by removing and discarding its topmost cylinder any number of times.

Find the maximum possible height of the stacks such that all of the stacks are exactly the same height. This means you must remove zero or more cylinders from the top of zero or more of the three stacks until they are all the same height, then return the height.

**Example**

There are and cylinders in the three stacks, with their heights in the three arrays. Remove the top 2 cylinders from (heights = [1, 2]) and from (heights = [1, 1]) so that the three stacks all are 2 units tall. Return as the answer.

**Note:** An empty stack is still a stack.

**Function Description**

Complete the *equalStacks* function in the editor below.

*equalStacks* has the following parameters:

*int h1[n1]:*the first array of heights*int h2[n2]:*the second array of heights*int h3[n3]:*the third array of heights

**Returns**

*int:*the height of the stacks when they are equalized

**Input Format**

The first line contains three space-separated integers, , , and , the numbers of cylinders in stacks , , and . The subsequent lines describe the respective heights of each cylinder in a stack *from top to bottom*:

- The second line contains space-separated integers, the cylinder heights in stack . The first element is the top cylinder of the stack.
- The third line contains space-separated integers, the cylinder heights in stack . The first element is the top cylinder of the stack.
- The fourth line contains space-separated integers, the cylinder heights in stack . The first element is the top cylinder of the stack.

**Constraints**

**Sample Input**

STDIN Function ----- -------- 5 3 4 h1[] size n1 = 5, h2[] size n2 = 3, h3[] size n3 = 4 3 2 1 1 1 h1 = [3, 2, 1, 1, 1] 4 3 2 h2 = [4, 3, 2] 1 1 4 1 h3 = [1, 1, 4, 1]

**Sample Output**

5

**Explanation**

Initially, the stacks look like this:

To equalize thier heights, remove the first cylinder from stacks and , and then remove the top two cylinders from stack (shown below).

The stack heights are reduced as follows:

Equal Stacks – Hacker Rank Solution

import java.util.Scanner; import java.util.Stack; /** * @author Techno-RJ * */ public class EqualStacks { static int equalStacks(int[] h1, int[] h2, int[] h3) { Stack<Integer> st1 = new Stack<Integer>(); Stack<Integer> st2 = new Stack<Integer>(); Stack<Integer> st3 = new Stack<Integer>(); int st1TotalHeight = 0, st2TotalHeight = 0, st3TotalHeight = 0; // pushing consolidated height into the stack instead of individual cylinder // height for (int i = h1.length - 1; i >= 0; i--) { st1TotalHeight += h1[i]; st1.push(st1TotalHeight); } for (int i = h2.length - 1; i >= 0; i--) { st2TotalHeight += h2[i]; st2.push(st2TotalHeight); } for (int i = h3.length - 1; i >= 0; i--) { st3TotalHeight += h3[i]; st3.push(st3TotalHeight); } while (true) { // If any stack is empty if (st1.isEmpty() || st2.isEmpty() || st3.isEmpty()) return 0; st1TotalHeight = st1.peek(); st2TotalHeight = st2.peek(); st3TotalHeight = st3.peek(); // If sum of all three stack are equal. if (st1TotalHeight == st2TotalHeight && st2TotalHeight == st3TotalHeight) return st1TotalHeight; // Finding the stack with maximum sum and // removing its top element. if (st1TotalHeight >= st2TotalHeight && st1TotalHeight >= st3TotalHeight) st1.pop(); else if (st2TotalHeight >= st1TotalHeight && st2TotalHeight >= st3TotalHeight) st2.pop(); else if (st3TotalHeight >= st2TotalHeight && st3TotalHeight >= st1TotalHeight) st3.pop(); } } public static void main(String[] args) { Scanner in = new Scanner(System.in); int n1 = in.nextInt(); int n2 = in.nextInt(); int n3 = in.nextInt(); int h1[] = new int[n1]; for (int h1_i = 0; h1_i < n1; h1_i++) { h1[h1_i] = in.nextInt(); } int h2[] = new int[n2]; for (int h2_i = 0; h2_i < n2; h2_i++) { h2[h2_i] = in.nextInt(); } int h3[] = new int[n3]; for (int h3_i = 0; h3_i < n3; h3_i++) { h3[h3_i] = in.nextInt(); } System.out.println(equalStacks(h1, h2, h3)); in.close(); } }