**Factorial Trailing Zeroes** **LeetCode Solution | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Solutions in C++**

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** Link for the Problem** – Factorial Trailing Zeroes– LeetCode Problem

Factorial Trailing Zeroes– LeetCode Problem

**Problem:**

Given an integer `n`

, return *the number of trailing zeroes in *`n!`

.

Note that `n! = n * (n - 1) * (n - 2) * ... * 3 * 2 * 1`

.

**Example 1:**

Input:n = 3Output:0Explanation:3! = 6, no trailing zero.

**Example 2:**

Input:n = 5Output:1Explanation:5! = 120, one trailing zero.

**Example 3:**

Input:n = 0Output:0

**Constraints:**

`0 <= n <= 10`

^{4}

Factorial Trailing Zeroes– LeetCode Solutions

Factorial Trailing ZeroesSolution in C++:

class Solution { public: int trailingZeroes(int n) { return n == 0 ? 0 : n / 5 + trailingZeroes(n / 5); } };

Factorial Trailing ZeroesSolution in Java:

class Solution { public int trailingZeroes(int n) { return n == 0 ? 0 : n / 5 + trailingZeroes(n / 5); } }

Factorial Trailing ZeroesSolution in Python:

class Solution: def trailingZeroes(self, n: int) -> int: return 0 if n == 0 else n // 5 + self.trailingZeroes(n // 5)