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Link for the Problem – Java If-Else – Hacker Rank Solution

Java If-Else – Hacker Rank Solution
 - HackerRank Solution

Problem

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

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Task

Given an integer, n, perform the following conditional actions:

• If n is odd, print Weird
• If n is even and in the inclusive range of 2 to 5, print Not Weird
• If n is even and in the inclusive range of 6 to 20 , print Weird
• If n is even and greater than 20, print Not Weird

Complete the stub code provided in your editor to print whether or not n is weird.

Input Format

A single line containing a positive integer, n.

Constraints

1<=n<=100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

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Example 0 :-

Sample Input 0

3

Sample Output 0

Weird

Example 1 :-

Sample Input 1

24

Sample Output1

Not Weird

Explanation

Sample Case 0: n=3n is odd and odd numbers are weird, so we print Weird.Sample Case 1:n=24 n>24 and n is even, so it isn’t weird. Thus, we print Not Weird.

Java If-Else – Hacker Rank Solution

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution 
{



    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args)
 {
        int N = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
        if(N%2!=0)
        {
            System.out.println("Weird");
        }
        else if(N >=2&&N<=5)
        {
            System.out.println("Not Weird");
        }
        else if(N>=6 && N <= 20)
        {    
            System.out.println("Weird");
        }
        else if(N>=20)
        {
            System.out.println("Not Weird");
        }
        scanner.close();
    }
}