Hello LinkedIn Users, Today we are going to share LinkedIn MATLAB Skill Assessment Answers. So, if you are a LinkedIn user, then you must give Skill Assessment Test. This Assessment Skill Test in LinkedIn is totally free and after completion of Assessment, you’ll earn a verified LinkedIn Skill Badge🥇 that will display on your profile and will help you in getting hired by recruiters.
Who can give this Skill Assessment Test?
Any LinkedIn User-
- Wants to increase chances for getting hire,
- Wants to Earn LinkedIn Skill Badge🥇🥇,
- Wants to rank their LinkedIn Profile,
- Wants to improve their Programming Skills,
- Anyone interested in improving their whiteboard coding skill,
- Anyone who wants to become a Software Engineer, SDE, Data Scientist, Machine Learning Engineer etc.,
- Any students who want to start a career in Data Science,
- Students who have at least high school knowledge in math and who want to start learning data structures,
- Any self-taught programmer who missed out on a computer science degree.
Here, you will find MATLAB Quiz Answers in Bold Color which are given below. These answers are updated recently and are 100% correct✅ answers of LinkedIn MATLAB Skill Assessment.
69% of professionals think verified skills are more important than college education. And 89% of hirers said they think skill assessments are an essential part of evaluating candidates for a job.
LinkedIn MATLAB Assessment Answers
Q1. From what distribution does the rand() function return value?
- normal
- poisson
- binomial
- uniform
Q2. Based on the code below, c is the \_ of a.
a = rand(1, 11);b = sort(a);c = b(1, ceil(end/2));
- median
- mode
- mean
- margin
Q3. What does the Profiler track?
- execution time
- command history
- errors
- the value of variables
Q4. Which code block contains the correct syntax for a while loop?
- [ ] a = 0;
do a = a + 1;while a < 5end
- [ ]
a = 0;while(a < 5) a = a + 1;
- [ ]
a = 0;while a < 5: a = a + 1;
- [x]
a = 0;while a < 5 a = a + 1;end
Q5. What does b contain?
a = 19 20 12 0 6 6 9 56 0 3 46 8 9 8 19 9 8 8 19 46 1 9 46 6 19
- [x] b =
56 0 9 8 - [ ] b =
8 19 19 46
Q6. You have written a function myfun and want to measure how long it takes to run. Which code segment will return in t the time in seconds it takes myfun to run?
- [ ] t = cputime(myfun());
- [x] tic;
myfun();toc;
- [ ] timer.start;
myfun()t = timer.stop;
- [ ] t = timer(myfun());
Q7. What is %% used for?
- argument placeholder
- block quotes
- code sections
- conversion specifier
Q8. What is the . character NOT used for?
- structure field access
- a decimal point
- cell array access
- element-wise operations
Q9. Which function could you use for multiple linear regression?
- polyval
- regress
- solve
- polyfit
Q10. For which of these arrays do mean, median, and mode return the same value?
- [0 1 1 1 2]
- [1 3 5 5 6]
- [0 1 1 1 1]
- [0 0 5 5 5]
Q11. You are in the middle of a long MATLAB session where you have performed many analyses and made many plots. You run the following commands, yet a figure window doesn’t pop up on the top of your screen with your plot. What might be the issue?
x = [-1:0.1:1];y = X.^2;plot(x, y)
- Your plot doesn’t plot in a figure window because figure was not called immediately in advance.
- Your plot syntax is incorrect.
- Your plot is in a figure window that was already open, hidden behind other windows on your screen.
- Your plot was saved to an image file but not displayed.
Q12. How do you access the value for the field name in structure S?
- S[‘name’]
- S.name
- S(‘name’)
- S{‘name’}
Q13. What built-in definition does i have?
- basic imaginary unit
- index function
- infinity
- index variable
Q14. Which statement is equivalent to this for loop?
a = [1 2 3; 4 5 6];b = zeros(size(a));
for i_row = 1:size(a, 1)
for i_col = 1:size(a, 2)
b(i_row, i_col) = a(i_row, i_col)^2;
endend
- b = a*a;
- b = a.^2;
- b = a^2;
- b = pow2(a);
Q15. You have plotted values of cosine from -10 to 10 and want to change the x-axis tick marks to every pi, from -3pi to 3pi. Which statement will do that?
- xticks(-3pi:3.14:3pi)
- xticks(-3pi:pi:3pi)
- xticks(linespace(-3pi(), 3pi(), pi()))
- xticks(linespace(-3pi, 3pi, pi)
Q16. What is the value of c?
a = ones(1,3);b = 1:3;c = conv(a,b)
- [-1 2 -1]
- [1 3 6 5 3]
- 6
- [1 -2 1]
Q17. Which function CANNOT be used to randomly sample data?
- datasample
- randi
- resample
- randperm
Q18. Which choice is correct syntax for a switch statement?
- [x] x = 7;
switch x case 2 disp(“two”); otherwise disp(“not two”);end
- [ ] x = 7;
switch x : case 2 disp(“two”); otherwise disp(“not two”);end
- [ ] x = 7;
switch x case 2 disp(“two”); else disp(“not two”);end
- [ ] x = 7;
switch x case 2 disp(“two”); default disp(“not two”);end
Q19. What is the result of this code?
a = 1;b = 2;c = 3;d = 4;e = c / (~a – b == c – d); Error
- [ ] c =
NaN
- [x] c =
Inf
- [ ] c =
-0.2500
Q20. What is true of a handle class object?
- When you pass a handle object to a function, a new object is made that is independent of the original.
- All copies of handle objects refer to the same underlying object.
- Handle object cannot reference one another.
- Handle object do not have a default eq function.
Q21. Which choice has a different final result in f10 than the other three?
- [ ] f10 = 1;
for i = 1:10 f10 = f10 * i;end
- [ ] f10 = factorial(10)
- [x] f10 = 1;
i = 1;while i <= 10 i = i + 1; f10 = i * f10;end
- [ ] f10 = prod(1:10)
Q22. Which choice will NOT give you a 5 x 5 identity matrix?
- [ ] a = rand(5);
round(a * inv(a))
- [ ] diag(ones(5, 1))
- [ ] identity(5)
- [ ] eye(5)
Q23. Which statement creates this structure?
dog = name: ‘Bindy’ breed: ‘border collie’ weight: 32 dog = struct(‘name’, ‘Bindy’; ‘breed’, ‘border collie’; ‘weight’, 32);
- [x]
dog.name = ‘Bindy’;dog.breed = ‘border collie’;dog.weight = 32;
- [ ]
dog = { ‘name’ : ‘Bindy’, ‘breed’ : ‘border collie’, ‘weight’: 32;}
- [ ]
dog(‘name’) = ‘Bindy’;dog(‘breed’) = ‘border collie’;dog(‘weight’) = 32;
Q24. my_func is a function as follows. What is the value of an at the end of the code beneath?
function a = my_func(a) a = a + 1;end——————a = 0;for i = 1:3 my_func(a);enda = my_func(a);
- 4
- 3
- 0
- 1
Q25. Which statement could create this cell array?
c = {[“hello world”]} {1×1 cell} {[“goodbye”]} {1×3 double}
- c = {“hello world” {“hello”} “goodbye” [1 2 ]};
- c = {“hello world” {“hello”} “goodbye” {[1 2 3]}};
- c = {“hello world” {“hello”} “goodbye” [1 2 3]};
- c = {“hello world” {“hello” “hello”} “goodbye” {[1 2 3]}};
Q26. Which choice adds b to each row of a?
a = ones(4, 4);b= [1 2 3 4];
- a = a + reshape(b, 4, 1);
- a = a + b’;
- a = a + repmat(b, 4, 1);
- a = a + [b b b b];
Q27. Which choice replaces all as with os?
- [ ] for i = 1:length(fruit)
fruit{i}(fruit{i} == a) == o;end
- [ ] for i = 1:length(fruit)
fruit(i)(fruit(i) == ‘a’) == ‘o’;end
- [x] for i = 1:length(fruit)
fruit{i}(fruit{i} == ‘a’) == ‘o’;end
- [ ] for i = 1:length(fruit)
fruit{i}(fruit{i} == ‘a’) == ‘o’;
Q28. Which statement returns the roots for the polynomial x^2 + 2x – 4?
- poly([1 2 -4])
- solve(x^2 + 2x – 4 == 0)
- polyfit(x^2 + 2x – 4 == 0)
- roots([1 2 -4])
Q29. Which choice is the proper syntax to append a new elements a to the end of 1x 2 dimensional cell array C?
- C = {C a};
- C = cellcat(C a)
- C = cat(2, {a}, C)
- C{end+1}=a
Q30. You have loaded a dataset of people’s heights into a 100 x 1 array called height. Which statement will return a 100 x 1 array, sim_height, with values from a normal distribution with the same mean and variance as your height data?
- sim_height = std(height) + mean(height) * randn(100, 1);
- sim_height = mean(height) + std(height) * randn(100, 1);
- sim_height = randn(std(height), mean(height), [100, 1]);
- sim_height = randn(mean(height), std(height), [100, 1]);
Q31. Which statement returns a cell array of the strings containing ‘burger’ from menu?
menu = {‘hot dog’ ‘corn dog’ ‘regular burger’ ‘cheeseburger’ ‘veggie burger’}
- menu{strfind(menu, ‘burger’)}
- menu(strfind(menu, ‘burger’))
- menu{contains(menu, ‘burger’)}
- menu(contains(menu, ‘burger’))
Q32. What is the set of possible values that a may contain?
a = randi(10, [1, 10]);a(3) = 11;a(a>2) = 12;
- 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
- 1, 2, 12
- 2, 11, 12
- 1, 12
Q33. Which statement is true about the sparse matrices?
- You can use the sparse function to remove empty cells from cell array variables.
- Sparse matrices always use less memory than their associated full matrices.
- Mixtures of sparse and full matrices can be combined in all of MATLAB’s built-in arithmetic operations.
- The sparse function requires its input to be a full matrix with at least 50% zero elements.
Q34. Which statement using logical indices will result in an error?
a = 1:10;
- b = a(a ~= 11)
- b = a(a == 1)
- b = a(a>6 && a<9)
- b = a(a | 1)
Q35. Which statement turns menu into the variable menu_string below?
menu = {‘hot dog’ ‘corn dog’ ‘regular burger’ ‘cheeseburger’ ‘veggie burger’}menu_string =
‘hot dog corn dog regular burger cheeseburger veggie burger’
- menu_string = cell2mat(join(menu, newline))
- menu_string = cell2mat(join(menu, ‘\n’))
- menu_string = join(menu, newline)
- menu_string = cell2mat(pad(menu))
Q36. Which code snippet sets a new random seed based on the current time and saves the current settings of the random number generator?
- rng_settings_curr = rng(‘shuffle’);
rng(time());rng_settings_curr = rng();
- rng_settings_curr = rand(‘shuffle’);
rng(‘shuffle’);rng_settings_curr = rng();
Q37. You have a matrix data in which each column is mono audio recording from a room in your house. You’ve noticed that each column has a very different mean and when you plot them all on the same graph, the spread across the y axis make it impossible to see anything. You want to subtract the mean from each column. Which code block will accomplish this?
- data_nomean = data – repmat(median(data), size(data, 1), 1);
- data_nomean = bsxfun(@minus, data, mean(data));
- data_nomean = zeros(size(data));
for i = 1:size(data, 1) data_nomean(i, 🙂 = data(i, 🙂 – mean(data(i, :));end
- data_nomean = zscore(data’);
Q38. Which code block results in an array b containing the mean values of each array within C?
- b = zeros(1, size(C, 2));
for i_C = 1:size(C, 2) b(i_C) = mean(C(i_C));end b = cellfun(@mean, C);
- b = zeros(1, size(C, 1));
for i_C = 1:size(C, 1) b(i_C) = mean(C{i_C}(:));end
- b = cellfun(@(m) mean(m(:)), C)
Q39. Which statement creates a logical array that is 1 if the element in passwords contains a digit and 0 if it does not?
passwords = {‘abcd’ ‘1234’ ‘qwerty’ ‘love1’};
- contains(password, ‘\d’)
- ~isempty(regexp(passwords, ‘\d’))
- cellfun(@(x) ~isempty(regexp(x, ‘\d’)), passwords)
- regexp(passwords, ‘\d’)
Q40. Which is NOT a function that adds text to a plot?
- title
- text
- label
- legend
Q41. Which code block most likely produced this graph?
- [ ] figure
x = rand(10,10);r = corrcoef(x);surf(r)colorbar
- [x] figure
x = rand(10,10);r = corrcoef(x);imagesc(r)colorbar
Q42. What kind of files are stored with the .mat extension?
- figure files
- script files
- function files
- stored variable files
Q43. You would like to randomly reorder every element in array a and put the result into another array b. Which code is NOT necessary to do that?
a = 1:10;
- [ ] b = a(randi(10, 1, 10));
m = perms(a);i = randi(factorial(10), 1);b = a(m(i, :))
- [ ] [s, j] = sort(rand(10, 1));
b = a(i);
- [ ] b = a(randperm(10));
Q44. Which statement returns 1 (true)?
a = ‘stand’b = “stand”
- a == b
- ischar(b)
- length(a) == length(b)
- class(a) == class(b)
Q45. Which does E contain?
C = {‘dog’ ‘cat’ ‘mouse’}D = {‘cow’ ‘piranha’ ‘mouse’}E = setdiff(C,D)
- E = {‘cat’} {‘dog’}
- E = {‘mouse’}
- E = {‘cat’} {‘cow’} {‘dog’} {‘piranha’}
- E =
Q46. Where in the UI can you see what variables have been created, their values, and their class?
- Editor
- command window
- details
- workspace
Q47. Given the following x and y coordinates, which choice calculates a linear regression for the x and y coordinates, and which plots the points of the x,y data and the regression line on the same graph?
x = 9.0646 6.4362 7.8266 8.3945 5.6135 4.8186 2.8862 10.9311 1.1908 3.2586y = 15.4357 11.0923 14.1417 14.9506 8.7687 8.0416 5.1662 20.5005 1.0978
- [x] coeff_line = polyfit(x,y,1)
x_line = floor(min(x)):0.1:ceil(max(x));y_line = polyval(coeff_line,x_line)
figure; plot(x,y,’o’)hold onplot(x_linemy_line)
- [ ] figure
plot(x,y,’o’)
coeff_line = polyfit(x,y,1);x_line = floor(min(x)):0.1:ceil(max(x));y_line = polyval(coeff_line,x_line);plot(x_line,y_line)
- [ ] figure
plot(x,y)
coeff_line = polyfit(x,y,1);x_line = floor(min(x)):0.1:ceil(max(x));y_line = polyval(coeff_line,x_line);hold on; plot(x_line,y_line)
- [ ] coeff_line = polyfit(x,y,1);
x_line = floor(min(x)):0.1:ceil(max(x));y_line = polyval(coeff_line,x_line);
figure; plot(x,y,’o’)hold onplot(x_line,y_line)
Q48. If you run this piece of code, you will get an error. Why?
a = [0 1 2 3; 4 5 6 7];a = a^2;
- You are attempting to multiply a non-square matrix by itself, causing a dimension mismatch.
- MATLAB does not allow you to square all the elements in the matrix in a single operation.
- You must use the ** operator instead of the ^ operator.
- You cannot square matrices that have a 0 as the first element.
Conclusion
Hopefully, this article will be useful for you to find all the Answers of MATLAB Skill Assessment available on LinkedIn for free and grab some premium knowledge with less effort. If this article really helped you in any way then make sure to share it with your friends on social media and let them also know about this amazing Skill Assessment Test. You can also check out our other course Answers. So, be with us guys we will share a lot more free courses and their exam/quiz solutions also and follow our Techno-RJ Blog for more updates.
FAQs
Is this Skill Assessment Test is free?
Yes MATLAB Assessment Quiz is totally free on LinkedIn for you. The only thing is needed i.e. your dedication towards learning.
When I will get Skill Badge?
Yes, if will Pass the Skill Assessment Test, then you will earn a skill badge that will reflect in your LinkedIn profile. For passing in LinkedIn Skill Assessment, you must score 70% or higher, then only you will get you skill badge.
How to participate in skill quiz assessment?
It’s good practice to update and tweak your LinkedIn profile every few months. After all, life is dynamic and (I hope) you’re always learning new skills. You will notice a button under the Skills & Endorsements tab within your LinkedIn Profile: ‘Take skill quiz.‘ Upon clicking, you will choose your desire skill test quiz and complete your assessment.