Longest Consecutive Sequence LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Longest Consecutive Sequence in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the Problem – Longest Consecutive Sequence– LeetCode Problem

Longest Consecutive Sequence– LeetCode Problem

Problem:

Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence.

You must write an algorithm that runs in O(n) time.

Example 1:

Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.

Example 2:

Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9

Constraints:

• 0 <= nums.length <= 105
• -109 <= nums[i] <= 109

Longest Consecutive Sequence– LeetCode Solutions

Longest Consecutive Sequence Solution in C++:

class Solution {
 public:
  int longestConsecutive(vector<int>& nums) {
    int ans = 0;
    unordered_set<int> seen{begin(nums), end(nums)};

    for (int num : nums) {
      // num is the start of a sequence
      if (seen.count(num - 1))
        continue;
      int length = 1;
      while (seen.count(++num))
        ++length;
      ans = max(ans, length);
    }

    return ans;
  }
};

Longest Consecutive Sequence Solution in Java:

class Solution {
  public int longestConsecutive(int[] nums) {
    int ans = 0;
    Set<Integer> seen = new HashSet<>();

    for (final int num : nums)
      seen.add(num);

    for (int num : nums) {
      // num is the start of a sequence
      if (seen.contains(num - 1))
        continue;
      int length = 1;
      while (seen.contains(++num))
        ++length;
      ans = Math.max(ans, length);
    }

    return ans;
  }
}

Longest Consecutive Sequence Solution in Python:

class Solution:
  def longestConsecutive(self, nums: List[int]) -> int:
    ans = 0
    seen = set(nums)

    for num in nums:
      if num - 1 in seen:
        continue
      length = 0
      while num in seen:
        num += 1
        length += 1
      ans = max(ans, length)

    return ans