**Majority Element** **LeetCode Solution | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Solutions in C++**

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** Link for the Problem** – Majority Element – LeetCode Problem

Majority Element– LeetCode Problem

**Problem:**

Given an array `nums`

of size `n`

, return *the majority element*.

The majority element is the element that appears more than `⌊n / 2⌋`

times. You may assume that the majority element always exists in the array.

**Example 1:**

Input:nums = [3,2,3]Output:3

**Example 2:**

Input:nums = [2,2,1,1,1,2,2]Output:2

**Constraints:**

`n == nums.length`

`1 <= n <= 5 * 10`

^{4}`-10`

^{9}<= nums[i] <= 10^{9}

Majority Element– LeetCode Solutions

Majority ElementSolution in C++:

class Solution { public: int majorityElement(vector<int>& nums) { int ans; int count = 0; for (const int num : nums) { if (count == 0) ans = num; count += num == ans ? 1 : -1; } return ans; } };

Majority ElementSolution in Java:

class Solution { public int majorityElement(int[] nums) { Integer ans = null; int count = 0; for (final int num : nums) { if (count == 0) ans = num; count += num == ans ? 1 : -1; } return ans; } }

Majority ElementSolution in Python:

class Solution: def majorityElement(self, nums: List[int]) -> int: ans = None count = 0 for num in nums: if count == 0: ans = num count += (1 if num == ans else -1) return ans