# Minimum Path Sum LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Minimum Path Sum in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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LeetCode is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews.

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Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the ProblemMinimum Path Sum– LeetCode Problem

`Minimum Path Sum– LeetCode Problem`

### Problem:

Given a `m x n` `grid` filled with non-negative numbers, find a path from top left to bottom right, which minimizes the sum of all numbers along its path.

Note: You can only move either down or right at any point in time.

Example 1:

```Input: grid = [[1,3,1],[1,5,1],[4,2,1]]
Output: 7
Explanation: Because the path 1 → 3 → 1 → 1 → 1 minimizes the sum.
```

Example 2:

```Input: grid = [[1,2,3],[4,5,6]]
Output: 12
```

Constraints:

• `m == grid.length`
• `n == grid[i].length`
• `1 <= m, n <= 200`
• `0 <= grid[i][j] <= 100`
`Minimum Path Sum– LeetCode Solutions`
`Minimum Path Sum in C++:`
```class Solution {
public:
int minPathSum(vector<vector<int>>& grid) {
const int m = grid.size();
const int n = grid.size();

for (int i = 0; i < m; ++i)
for (int j = 0; j < n; ++j)
if (i > 0 && j > 0)
grid[i][j] += min(grid[i - 1][j], grid[i][j - 1]);
else if (i > 0)
grid[i] += grid[i - 1];
else if (j > 0)
grid[j] += grid[j - 1];

return grid[m - 1][n - 1];
}
};```
`Minimum Path Sum in Java:`
```class Solution {
public int minPathSum(int[][] grid) {
final int m = grid.length;
final int n = grid.length;

for (int i = 0; i < m; ++i)
for (int j = 0; j < n; ++j)
if (i > 0 && j > 0)
grid[i][j] += Math.min(grid[i - 1][j], grid[i][j - 1]);
else if (i > 0)
grid[i] += grid[i - 1];
else if (j > 0)
grid[j] += grid[j - 1];

return grid[m - 1][n - 1];
}
}```
`Minimum Path Sum in Python:`
```class Solution:
def minPathSum(self, grid: List[List[int]]) -> int:
m = len(grid)
n = len(grid)

for i in range(m):
for j in range(n):
if i > 0 and j > 0:
grid[i][j] += min(grid[i - 1][j], grid[i][j - 1])
elif i > 0:
grid[i] += grid[i - 1]
elif j > 0:
grid[j] += grid[j - 1]

return grid[m - 1][n - 1]``` #### Ads Blocker Detected!!!

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