Playing With Characters in C | HackerRank Programming Solutions | HackerRank C Solutions

Hello Programmers/Coders, Today we are going to share solutions of Programming problems of HackerRank of Programming Language C . At Each Problem with Successful submission with all Test Cases Passed, you will get an score or marks. And after solving maximum problems, you will be getting stars. This will highlight you profile to the recruiters.

In this post, you will find the solution for Playing With Characters in C-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.

Use “Ctrl+F” To Find Any Questions Answer. & For Mobile User, You Just Need To Click On Three dots In Your Browser & You Will Get A “Find” Option There. Use These Option to Get Any Random Questions Answer.

C is one of the most widely used Programming Languages. it is basically used to build Operating System. C was developed by Dennis Ritchie in 1972. Below are some examples of C Programming which might you understanding the basics of C Programming.

Objective

This challenge will help you to learn how to take a character, a string and a sentence as input in C.

To take a single character  as input, you can use scanf("%c", &ch ); and printf("%c", ch) writes a character specified by the argument char to stdout

char ch;
scanf("%c", &ch);
printf("%c", ch);

This piece of code prints the character .

You can take a string as input in C using scanf(“%s”, s). But, it accepts string only until it finds the first space.

In order to take a line as input, you can use scanf("%[^\n]%*c", s); where  is defined as char s[MAX_LEN] where  is the maximum size of . Here, [] is the scanset character. ^\n stands for taking input until a newline isn’t encountered. Then, with this %*c, it reads the newline character and here, the used * indicates that this newline character is discarded.

Note: The statement: scanf("%[^\n]%*c", s); will not work because the last statement will read a newline character, \n, from the previous line. This can be handled in a variety of ways. One way is to use scanf("\n"); before the last statement.

Task

You have to print the character, , in the first line. Then print  in next line. In the last line print the sentence, .

Input Format

First, take a character,  as input.
Then take the string,  as input.
Lastly, take the sentence  as input.

Constraints

Strings for  and  will have fewer than 100 characters, including the newline.

Output Format

Print three lines of output. The first line prints the character, .
The second line prints the string, .
The third line prints the sentence, .

Sample Input 0

C
Language
Welcome To C!!

Sample Output 0

C
Language
Welcome To C!!

Playing With Characters – Hacker Rank Solution

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
#define MAX_LIMIT 40
int main() 
{  
    char ch;
    char s[MAX_LIMIT];
    char sen[MAX_LIMIT];
    scanf("%c",&ch);
    scanf("%s",&s);
    scanf("\n");
    scanf("%[^\n]%*c", sen);
    printf("%c\n%s\n%s",ch,s,sen); 
    // Playing With Characters - Hacker Rank Solution END
    return 0;
}