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In this post, you will find the solution for the **Remove Duplicates from Sorted List** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Remove Duplicates from Sorted List– LeetCode Problem

Remove Duplicates from Sorted List– LeetCode Problem

**Problem:**

Given the `head`

of a sorted linked list, *delete all duplicates such that each element appears only once*. Return *the linked list sorted as well*.

**Example 1:**

Input:head = [1,1,2]Output:[1,2]

**Example 2:**

Input:head = [1,1,2,3,3]Output:[1,2,3]

**Constraints:**

- The number of nodes in the list is in the range
`[0, 300]`

. `-100 <= Node.val <= 100`

- The list is guaranteed to be
**sorted**in ascending order.

Remove Duplicates from Sorted List– LeetCode Solutions

Remove Duplicates from Sorted List in C++:

class Solution { public: ListNode* deleteDuplicates(ListNode* head) { ListNode* curr = head; while (curr) { while (curr->next && curr->val == curr->next->val) curr->next = curr->next->next; curr = curr->next; } return head; } };

Remove Duplicates from Sorted List in Java:

class Solution { public ListNode deleteDuplicates(ListNode head) { ListNode curr = head; while (curr != null) { while (curr.next != null && curr.val == curr.next.val) curr.next = curr.next.next; curr = curr.next; } return head; } }

Remove Duplicates from Sorted List in Python:

class Solution: def deleteDuplicates(self, head: ListNode) -> ListNode: curr = head while curr: while curr.next and curr.val == curr.next.val: curr.next = curr.next.next curr = curr.next return head