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In this post, you will find the solution for the **Single Number II** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Single Number II– LeetCode Problem

Single Number II– LeetCode Problem

**Problem:**

Given an integer array `nums`

where every element appears **three times** except for one, which appears **exactly once**. *Find the single element and return it*.

You must implement a solution with a linear runtime complexity and use only constant extra space.

**Example 1:**

Input:nums = [2,2,3,2]Output:3

**Example 2:**

Input:nums = [0,1,0,1,0,1,99]Output:99

**Constraints:**

`1 <= nums.length <= 3 * 10`

^{4}`-2`

^{31}<= nums[i] <= 2^{31}- 1- Each element in
`nums`

appears exactly**three times**except for one element which appears**once**.

Single Number II– LeetCode Solutions

Single Number II Solution in C++:

class Solution { public: int singleNumber(vector<int>& nums) { int ones = 0; int twos = 0; for (const int num : nums) { ones ^= (num & ~twos); twos ^= (num & ~ones); } return ones; } };

Single Number II Solution in Java:

class Solution { public int singleNumber(int[] nums) { int ones = 0; int twos = 0; for (final int num : nums) { ones ^= (num & ~twos); twos ^= (num & ~ones); } return ones; } }

Single Number II Solution in Python:

class Solution: def singleNumber(self, nums: List[int]) -> int: ones = 0 twos = 0 for num in nums: ones ^= (num & ~twos) twos ^= (num & ~ones) return ones