Find Minimum in Rotated Sorted Array II LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [๐Ÿ’ฏCorrect]

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In this post, you will find the solution for the Find Minimum in Rotated Sorted Array II in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the Problem – Find Minimum in Rotated Sorted Array IIโ€“ LeetCode Problem

Find Minimum in Rotated Sorted Array IIโ€“ LeetCode Problem

Problem:

Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,4,4,5,6,7] might become:

  • [4,5,6,7,0,1,4] if it was rotated 4 times.
  • [0,1,4,4,5,6,7] if it was rotated 7 times.

Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]].

Given the sorted rotated array nums that may contain duplicates, return the minimum element of this array.

You must decrease the overall operation steps as much as possible.

Example 1:

Input: nums = [1,3,5]
Output: 1

Example 2:

Input: nums = [2,2,2,0,1]
Output: 0

Constraints:

  • n == nums.length
  • 1 <= n <= 5000
  • -5000 <= nums[i] <= 5000
  • nums is sorted and rotated between 1 and n times.
Find Minimum in Rotated Sorted Array IIโ€“ LeetCode Solutions
Find Minimum in Rotated Sorted Array II Solution in C++:
class Solution {
 public:
  int findMin(vector<int>& nums) {
    int l = 0;
    int r = nums.size() - 1;

    while (l < r) {
      const int m = l + (r - l) / 2;
      if (nums[m] == nums[r])
        --r;
      else if (nums[m] < nums[r])
        r = m;
      else
        l = m + 1;
    }

    return nums[l];
  }
};
Find Minimum in Rotated Sorted Array II Solution in Java:
class Solution {
  public int findMin(int[] nums) {
    int l = 0;
    int r = nums.length - 1;

    while (l < r) {
      final int m = l + (r - l) / 2;
      if (nums[m] == nums[r])
        --r;
      else if (nums[m] < nums[r])
        r = m;
      else
        l = m + 1;
    }

    return nums[l];
  }
}
Find Minimum in Rotated Sorted Array II Solution in Python:
class Solution:
  def findMin(self, nums: List[int]) -> int:
    l = 0
    r = len(nums) - 1

    while l < r:
      m = (l + r) // 2
      if nums[m] == nums[r]:
        r -= 1
      elif nums[m] < nums[r]:
        r = m
      else:
        l = m + 1

    return nums[l]

296 thoughts on “Find Minimum in Rotated Sorted Array II LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [๐Ÿ’ฏCorrect]”

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