**Two Sum II – Input Array Is Sorted** **LeetCode Problem | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Solutions in C++**

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** Link for the Problem** – Two Sum II – Input Array Is Sorted– LeetCode Problem

Two Sum II - Input Array Is Sorted– LeetCode Problem

**Problem:**

Given a **1-indexed** array of integers `numbers`

that is already ** sorted in non-decreasing order**, find two numbers such that they add up to a specific

`target`

number. Let these two numbers be `numbers[index`_{1}]

and `numbers[index`_{2}]

where `1 <= index`_{1} < index_{2} <= numbers.length

.Return* the indices of the two numbers, *`index`

_{1}* and *`index`

_{2}*, added by one as an integer array *

`[index`_{1}, index_{2}]

*of length 2.*

The tests are generated such that there is **exactly one solution**. You **may not** use the same element twice.

Your solution must use only constant extra space.

**Example 1:**

Input:numbers = [2,7,11,15], target = 9Output:[1,2]Explanation:The sum of 2 and 7 is 9. Therefore, index_{1}= 1, index_{2}= 2. We return [1, 2].

**Example 2:**

Input:numbers = [2,3,4], target = 6Output:[1,3]Explanation:The sum of 2 and 4 is 6. Therefore index_{1}= 1, index_{2}= 3. We return [1, 3].

**Example 3:**

Input:numbers = [-1,0], target = -1Output:[1,2]Explanation:The sum of -1 and 0 is -1. Therefore index_{1}= 1, index_{2}= 2. We return [1, 2].

**Constraints:**

`2 <= numbers.length <= 3 * 10`

^{4}`-1000 <= numbers[i] <= 1000`

`numbers`

is sorted in**non-decreasing order**.`-1000 <= target <= 1000`

- The tests are generated such that there is
**exactly one solution**.

Two Sum II - Input Array Is Sorted– LeetCode Solutions

Two Sum II - Input Array Is SortedSolution in C++:

class Solution { public: vector<int> twoSum(vector<int>& numbers, int target) { int l = 0; int r = numbers.size() - 1; while (numbers[l] + numbers[r] != target) if (numbers[l] + numbers[r] < target) ++l; else --r; return {l + 1, r + 1}; } };

Two Sum II - Input Array Is SortedSolution in Java:

class Solution { public int[] twoSum(int[] numbers, int target) { int l = 0; int r = numbers.length - 1; while (numbers[l] + numbers[r] != target) if (numbers[l] + numbers[r] < target) ++l; else --r; return new int[] {l + 1, r + 1}; } }

Two Sum II - Input Array Is SortedSolution in Python:

class Solution: def twoSum(self, numbers: List[int], target: int) -> List[int]: l = 0 r = len(numbers) - 1 while l < r: sum = numbers[l] + numbers[r] if sum == target: return [l + 1, r + 1] if sum < target: l += 1 else: r -= 1