Two Sum III – Data structure design LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Link for the ProblemTwo Sum III – Data structure design– LeetCode Problem

Two Sum III - Data structure design– LeetCode Problem

Problem:

Design a data structure that accepts a stream of integers and checks if it has a pair of integers that sum up to a particular value.

Implement the TwoSum class:

  • TwoSum() Initializes the TwoSum object, with an empty array initially.
  • void add(int number) Adds number to the data structure.
  • boolean find(int value) Returns true if there exists any pair of numbers whose sum is equal to value, otherwise, it returns false.

EXAMPLE 1:

Input
["TwoSum", "add", "add", "add", "find", "find"]
[[], [1], [3], [5], [4], [7]]
Output
[null, null, null, null, true, false]
Explanation:
TwoSum twoSum = new TwoSum(); twoSum.add(1); // [] --> [1] twoSum.add(3); // [1] --> [1,3] twoSum.add(5); // [1,3] --> [1,3,5] twoSum.find(4); // 1 + 3 = 4, return true twoSum.find(7); // No two integers sum up to 7, return false

Constraints:

  • -105 <= number <= 105
  • -231 <= value <= 231 - 1
  • At most 5 * 104 calls will be made to add and find.
Two Sum III - Data structure design– LeetCode Solutions
Two Sum III - Data structure design Solution in C++:
class TwoSum {
 public:
  void add(int number) {
    ++count[number];
  }

  bool find(int value) {
    for (const auto& [key, freq] : count) {
      const int remain = value - key;
      if (key == remain && freq > 1)
        return true;
      if (key != remain && count.count(remain))
        return true;
    }

    return false;
  }

 private:
  unordered_map<int, int> count;
};
Two Sum III - Data structure design Solution in Java:
class TwoSum {
  public void add(int number) {
    count.put(number, count.getOrDefault(number, 0) + 1);
  }

  public boolean find(int value) {
    for (Map.Entry<Integer, Integer> entry : count.entrySet()) {
      final int key = entry.getKey();
      final int remain = value - key;
      if (key == remain && entry.getValue() > 1)
        return true;
      if (key != remain && count.containsKey(remain))
        return true;
    }

    return false;
  }

  private HashMap<Integer, Integer> count = new HashMap<>();
}
Two Sum III - Data structure design Solution in Python:
class TwoSum:
  def __init__(self):
    self.count = Counter()

  def add(self, number: int) -> None:
    self.count[number] += 1

  def find(self, value: int) -> bool:
    for key, freq in self.count.items():
      remain = value - key
      if key == remain and freq > 1:
        return True
      if key != remain and remain in self.count:
        return True

    return False

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