Letter Combinations of a Phone Number LeetCode Problem | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Problems C++
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Link for the Problem – Letter Combinations of a Phone Number– LeetCode Problem
Letter Combinations of a Phone Number– LeetCode Problem
Problem:
Given a string containing digits from 2-9
inclusive, return all possible letter combinations that the number could represent. Return the answer in any order.
A mapping of digits to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters.
![Letter Combinations of a Phone Number LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct] 2 200px Telephone keypad2.svg](https://upload.wikimedia.org/wikipedia/commons/thumb/7/73/Telephone-keypad2.svg/200px-Telephone-keypad2.svg.png)
Example 1:
Input: digits = "23" Output: ["ad","ae","af","bd","be","bf","cd","ce","cf"]
Example 2:
Input: digits = "" Output: []
Example 3:
Input: digits = "2" Output: ["a","b","c"]
Constraints:
0 <= digits.length <= 4
digits[i]
is a digit in the range['2', '9']
.
Letter Combinations of a Phone Number– LeetCode Solutions
class Solution { public: vector<string> letterCombinations(string digits) { if (digits.empty()) return {}; vector<string> ans; dfs(digits, 0, "", ans); return ans; } private: const vector<string> digitToLetters{"", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}; void dfs(const string& digits, int i, string&& path, vector<string>& ans) { if (i == digits.length()) { ans.push_back(path); return; } for (const char letter : digitToLetters[digits[i] - '0']) { path.push_back(letter); dfs(digits, i + 1, move(path), ans); path.pop_back(); } } };
class Solution { public List<String> letterCombinations(String digits) { if (digits.isEmpty()) return new ArrayList<>(); List<String> ans = new ArrayList<>(); ans.add(""); final String[] digitToLetters = {"", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}; for (final char d : digits.toCharArray()) { List<String> temp = new ArrayList<>(); for (final String s : ans) for (final char c : digitToLetters[d - '0'].toCharArray()) temp.add(s + c); ans = temp; } return ans; } }
class Solution: def letterCombinations(self, digits: str) -> List[str]: if not digits: return [] ans = [''] digitToLetters = ['', '', 'abc', 'def', 'ghi', 'jkl', 'mno', 'pqrs', 'tuv', 'wxyz'] for d in digits: temp = [] for s in ans: for c in digitToLetters[ord(d) - ord('0')]: temp.append(s + c) ans = temp return
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