# A Very Big Sum in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

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#### Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results.

• It is easy to understand.
• Algorithm is a step-wise representation of a solution to a given problem.
• In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the ProblemA Very Big Sum– Hacker Rank Solution

`A Very Big Sum – Hacker Rank Solution`

### Problem:

In this challenge, you are required to calculate and print the sum of the elements in an array, keeping in mind that some of those integers may be quite large.

Function Description

Complete the aVeryBigSum function in the editor below. It must return the sum of all array elements.

aVeryBigSum has the following parameter(s):

• int ar[n]: an array of integers .

Return

• long: the sum of all array elements

Input Format

The first line of the input consists of an integer .
The next line contains  space-separated integers contained in the array.

Output Format

Return the integer sum of the elements in the array.

Constraints

Sample Input

```5
1000000001 1000000002 1000000003 1000000004 1000000005
```

Output

```5000000015
```

Note:

The range of the 32-bit integer is

.When we add several integer values, the resulting sum might exceed the above range. You might need to use long int C/C++/Java to store such sums.

`A Very Big Sum– Hacker Rank Solution`
```import java.util.Scanner;

/**
* @author Techno-RJ
*
*/
public class AVeryBigSum {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
long sum = 0;

for (int arr_i = 0; arr_i < n; arr_i++) {
sum += in.nextLong();
}
System.out.println(sum);
in.close();

}
}```  