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Introduction To Algorithm
The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results.
Advantages of Algorithms:
- It is easy to understand.
- Algorithm is a step-wise representation of a solution to a given problem.
- In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.
Link for the Problem – Alternating Characters – Hacker Rank Solution
Alternating Characters – Hacker Rank Solution
Problem:
You are given a string containing characters and only. Your task is to change it into a string such that there are no matching adjacent characters. To do this, you are allowed to delete zero or more characters in the string.
Your task is to find the minimum number of required deletions.
Example
Remove an at positions and to make in deletions.
Function Description
Complete the alternatingCharacters function in the editor below.
alternatingCharacters has the following parameter(s):
- string s: a string
Returns
- int: the minimum number of deletions required
Input Format
The first line contains an integer , the number of queries.
The next lines each contain a string to analyze.
Constraints
- Each string will consist only of characters and .
Sample Input
5 AAAA BBBBB ABABABAB BABABA AAABBB
Sample Output
3 4 0 0 4
Explanation
The characters marked red are the ones that can be deleted so that the string does not have matching adjacent characters.
![Alternating Characters in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct] 2 image](https://s3.amazonaws.com/hr-assets/0/1502450721-a0a2e9b5bd-alternatingCharacter2.png)
Alternating Characters – Hacker Rank Solution
import java.util.Scanner; /** * @author Techno-RJ * */ public class AlternatingCharacters { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); for (int i = 0; i < n; i++) { String tmp = sc.next(); int count = 0; for (int j = 1; j < tmp.length(); j++) { if (tmp.charAt(j - 1) == tmp.charAt(j)) { count++; } } System.out.println(count); } sc.close(); } }