Anagram in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

Hello Programmers/Coders, Today we are going to share solutions of Programming problems of HackerRank, Algorithm Solutions of Problem Solving Section in Java. At Each Problem with Successful submission with all Test Cases Passed, you will get an score or marks. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for Anagram in Java-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.

Use “Ctrl+F” To Find Any Questions Answer. & For Mobile User, You Just Need To Click On Three dots In Your Browser & You Will Get A “Find” Option There. Use These Option to Get Any Random Questions Answer.

Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results. 

Advantages of Algorithms:

• It is easy to understand.
• Algorithm is a step-wise representation of a solution to a given problem.
• In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the Problem – Anagram – Hacker Rank Solution

Anagram – Hacker Rank Solution

Problem:

Two words are anagrams of one another if their letters can be rearranged to form the other word.

Given a string, split it into two contiguous substrings of equal length. Determine the minimum number of characters to change to make the two substrings into anagrams of one another.

Example

Break  into two parts: ‘abc’ and ‘cde’. Note that all letters have been used, the substrings are contiguous and their lengths are equal. Now you can change ‘a’ and ‘b’ in the first substring to ‘d’ and ‘e’ to have ‘dec’ and ‘cde’ which are anagrams. Two changes were necessary.

Function Description

Complete the anagram function in the editor below.

anagram has the following parameter(s):

• string s: a string

Returns

• int: the minimum number of characters to change or -1.

Input Format

The first line will contain an integer, , the number of test cases.
Each test case will contain a string .

Constraints

•  consists only of characters in the range ascii[a-z].

Sample Input

6
aaabbb
ab
abc
mnop
xyyx
xaxbbbxx

Sample Output

3
1
-1
2
0
1

Explanation

Test Case #01: We split  into two strings =’aaa’ and =’bbb’. We have to replace all three characters from the first string with ‘b’ to make the strings anagrams.

Test Case #02: You have to replace ‘a’ with ‘b’, which will generate “bb”.

Test Case #03: It is not possible for two strings of unequal length to be anagrams of one another.

Test Case #04: We have to replace both the characters of first string (“mn”) to make it an anagram of the other one.

Test Case #05:  and  are already anagrams of one another.

Test Case #06: Here S1 = “xaxb” and S2 = “bbxx”. You must replace ‘a’ from S1 with ‘b’ so that S1 = “xbxb”.

Anagram – Hacker Rank Solution

import java.util.Scanner;

/**
 * @author Techno-RJ
 *
 */
public class Anagram {
	static int anagram(String s) {
		int minNoOfChanes = 0;
		if ((s.length() & 1) == 1)
			return -1;
		int charFreq[] = new int[26];
		for (int i = 0; i < s.length(); i++) {
			int index = s.charAt(i) - 'a';
			if (i < s.length() / 2) {
				charFreq[index]++;
			} else {
				charFreq[index]--;
			}
		}
		for (int i = 0; i < 26; i++) {
			if (charFreq[i] > 0) {
				minNoOfChanes += charFreq[i];
			}

		}
		return minNoOfChanes;
	}

	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		int q = in.nextInt();
		for (int a0 = 0; a0 < q; a0++) {
			String s = in.next();
			int result = anagram(s);
			System.out.println(result);
			in.close();
		}
	}
}