Binary Tree Nodes in SQL | HackerRank Programming Solutions | HackerRank SQL Solutions

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In this post, you will find the solution for Binary Tree Nodes in SQL-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.

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Introduction To SQL

SQL stands for Structured Query Language. SQL is used to create, remove, alter the database and database objects in a database management system and to store, retrieve, update the data in a database. SQL is a standard language for creating, accessing, manipulating database management system. SQL works for all modern relational database management systems, like SQL Server, Oracle, MySQL, etc.

  • It is a standard language for Relational Database System. It enables a user to create, read, update and delete relational databases and tables.
  • All the RDBMS like MySQL, Informix, Oracle, MS Access and SQL Server use SQL as their standard database language.
  • SQL allows users to query the database in a number of ways, using English-like statements.

Link for the ProblemBinary Tree Nodes SQl – Hacker Rank Solution

Binary Tree Nodes SQl – Hacker Rank Solution

Problem:

You are given a table, BST, containing two columns: and P, where N represents the value of a node in Binary Tree, and P is the parent of N.

1443818507 5095ab9853 1

Write a query to find the node type of Binary Tree ordered by the value of the node. Output one of the following for each node:

  • Root: If node is root node.
  • Leaf: If node is leaf node.
  • Inner: If node is neither root nor leaf node.

Sample Input

Binary Tree Nodes

Sample Output

1 Leaf
2 Inner
3 Leaf
5 Root
6 Leaf
8 Inner
9 Leaf


Explanation

The Binary Tree below illustrates the sample:

Binary Tree Nodes
Binary Tree Nodes SQl – Hacker Rank Solution
SELECT BT.N,
CASE
    WHEN BT.P IS NULL THEN 'Root'
    WHEN EXISTS (SELECT B.P FROM BST B WHERE B.P = BT.N) THEN 'Inner'        
    ELSE 'Leaf'
END
FROM BST AS BT 
ORDER BY BT.N

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