CamelCase in Algorithm | HackerRank Programming Solutions | HackerRank Problem Solving Solutions in Java [💯Correct]

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In this post, you will find the solution for CamelCase in Java-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.

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Introduction To Algorithm

The word Algorithm means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results. 

Advantages of Algorithms:

  • It is easy to understand.
  • Algorithm is a step-wise representation of a solution to a given problem.
  • In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

Link for the ProblemCamelCase – Hacker Rank Solution

CamelCase – Hacker Rank Solution

Problem:

There is a sequence of words in CamelCase as a string of letters, , having the following properties:

  • It is a concatenation of one or more words consisting of English letters.
  • All letters in the first word are lowercase.
  • For each of the subsequent words, the first letter is uppercase and rest of the letters are lowercase.

Given , determine the number of words in .

Example

There are  words in the string: ‘one’, ‘Two’, ‘Three’.

Function Description

Complete the camelcase function in the editor below.

camelcase has the following parameter(s):

  • string s: the string to analyze

Returns

  • int: the number of words in 

Input Format

A single line containing string .

Constraints

image 85

Sample Input

saveChangesInTheEditor

Sample Output

5

Explanation

String  contains five words:

  1. save
  2. Changes
  3. In
  4. The
  5. Editor
CamelCase – Hacker Rank Solution
import java.util.Scanner;

/**
 * @author Techno-RJ
 *
 */
public class CamelCase {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		String s = sc.next();
		int count = 1;
		for (int i = 0; i < s.length(); i++) {
			if (s.charAt(i) >= 65 && s.charAt(i) <= 90) {
				count++;
			}
		}
		System.out.println(count);
		sc.close();

	}
}

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