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In this post, you will find the solution for **Climbing the Leaderboard** **in Java-HackerRank Problem**. We are providing the **correct and tested solutions** of coding problems present on **HackerRank**. If you are not able to solve any problem, then you can take help from our Blog/website.

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**Introduction To Algorithm**

The word **Algorithm** means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results.

**Advantages of Algorithms:**

- It is easy to understand.
- Algorithm is a step-wise representation of a solution to a given problem.
- In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

** Link for the Problem** – Climbing the Leaderboard – Hacker Rank Solution

Climbing the Leaderboard – Hacker Rank Solution

**Problem:**

An arcade game player wants to climb to the top of the leaderboard and track their ranking. The game uses Dense Ranking, so its leaderboard works like this:

- The player with the highest score is ranked number on the leaderboard.
- Players who have equal scores receive the same ranking number, and the next player(s) receive the immediately following ranking number.

**Function Description**

Complete the *climbingLeaderboard* function in the editor below.

climbingLeaderboard has the following parameter(s):

*int ranked[n]*: the leaderboard scores*int player[m]*: the player’s scores

**Returns**

*int[m]:*the player’s rank after each new score

**Input Format**

Array: ranked1001005040402010 Array: player52550120

7

100 100 50 40 40 20 10

4

5 25 50 120

**Sample Output 1**

6421

**Explanation 1**

Alice starts playing with players already on the leaderboard, which looks like this:

After Alice finishes game , her score is and her ranking is :

After Alice finishes game , her score is and her ranking is :

After Alice finishes game , her score is and her ranking is tied with Caroline at :

After Alice finishes game , her score is and her ranking is :

Array: ranked1009090807560 Array: player50657790102

6

100 90 90 80 75 60

5

50 65 77 90 102

**Sample Output 2**

65421

Climbing the Leaderboard – Hacker Rank Solution

import java.util.Scanner; /** * @author Techno-RJ * */ public class ClimbingTheLeaderboard { public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); int[] scores = new int[n]; scores[0] = in.nextInt(); int k = 1, counter = 0; for (int scores_i = 1; scores_i < n; scores_i++) { int temp = in.nextInt(); if (temp != scores[k - 1]) { scores[k++] = temp; } else { counter++; } } for (int i = scores.length - 1; i >= 0 && counter > 0; i--) { counter--; scores[i] = Integer.MIN_VALUE; } int m = in.nextInt(); for (int alice_i = 0; alice_i < m; alice_i++) { int tmp = in.nextInt(); if (tmp > scores[0]) { System.out.println(1); } else if (tmp < scores[scores.length - 1]) { System.out.println(scores.length + 1); } else { System.out.println(binarySearch(scores, tmp) + 1); } } in.close(); } private static int binarySearch(int[] a, int key) { int lo = 0; int hi = a.length - 1; while (lo <= hi) { int mid = lo + (hi - lo) / 2; if (a[mid] == key) { return mid; } else if (a[mid] < key && key < a[mid - 1]) { return mid; } else if (a[mid] > key && key >= a[mid + 1]) { return mid + 1; } else if (a[mid] < key) { hi = mid - 1; } else if (a[mid] > key) { lo = mid + 1; } } return -1; } }

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