Combination Sum II LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [๐Ÿ’ฏCorrect]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Combination Sum II in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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About LeetCode

LeetCode is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews. 

LeetCode is for software engineers who are looking to practice technical questions and advance their skills. Mastering the questions in each level on LeetCode is a good way to prepare for technical interviews and keep your skills sharp. They also have a repository of solutions with the reasoning behind each step.

LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either EasyMedium, or Hard.

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  • Recursion, etc.

Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the ProblemCombination Sum IIโ€“ LeetCode Problem

Combination Sum IIโ€“ LeetCode Problem


Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sum to target.

Each number in candidates may only be used once in the combination.

Note: The solution set must not contain duplicate combinations.

Example 1:

Input: candidates = [10,1,2,7,6,1,5], target = 8

Example 2:

Input: candidates = [2,5,2,1,2], target = 5


  • 1 <= candidates.length <= 100
  • 1 <= candidates[i] <= 50
  • 1 <= target <= 30
Combination Sum IIโ€“ LeetCode Solutions
class Solution {
  vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {
    vector<vector<int>> ans;

    sort(begin(candidates), end(candidates));
    dfs(candidates, 0, target, {}, ans);

    return ans;

  void dfs(const vector<int>& A, int s, int target, vector<int>&& path,
           vector<vector<int>>& ans) {
    if (target < 0)
    if (target == 0) {

    for (int i = s; i < A.size(); ++i) {
      if (i > s && A[i] == A[i - 1])
      dfs(A, i + 1, target - A[i], move(path), ans);
class Solution {
  public List<List<Integer>> combinationSum2(int[] candidates, int target) {
    List<List<Integer>> ans = new ArrayList<>();

    dfs(0, candidates, target, new ArrayList<>(), ans);

    return ans;

  private void dfs(int s, int[] candidates, int target, List<Integer> path,
                   List<List<Integer>> ans) {
    if (target < 0)
    if (target == 0) {
      ans.add(new ArrayList<>(path));

    for (int i = s; i < candidates.length; ++i) {
      if (i > s && candidates[i] == candidates[i - 1])
      dfs(i + 1, candidates, target - candidates[i], path, ans);
      path.remove(path.size() - 1);
class Solution:
  def combinationSum2(self, candidates: List[int], target: int) -> List[List[int]]:
    ans = []

    def dfs(s: int, target: int, path: List[int]) -> None:
      if target < 0:
      if target == 0:

      for i in range(s, len(candidates)):
        if i > s and candidates[i] == candidates[i - 1]:
        dfs(i + 1, target - candidates[i], path + [candidates[i]])

    dfs(0, target, [])

    return ans

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