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Link for the Problem – Count and Say– LeetCode Problem
Count and Say– LeetCode Problem
Problem:
The count-and-say sequence is a sequence of digit strings defined by the recursive formula:
countAndSay(1) = "1"
countAndSay(n)
is the way you would “say” the digit string fromcountAndSay(n-1)
, which is then converted into a different digit string.
To determine how you “say” a digit string, split it into the minimal number of groups so that each group is a contiguous section all of the same character. Then for each group, say the number of characters, then say the character. To convert the saying into a digit string, replace the counts with a number and concatenate every saying.
For example, the saying and conversion for digit string "3322251"
:
![Count and Say LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct] 2 countandsay](https://assets.leetcode.com/uploads/2020/10/23/countandsay.jpg)
Given a positive integer n
, return the nth
term of the count-and-say sequence.
Example 1:
Input: n = 1 Output: "1" Explanation: This is the base case.
Example 2:
Input: n = 4 Output: "1211" Explanation: countAndSay(1) = "1" countAndSay(2) = say "1" = one 1 = "11" countAndSay(3) = say "11" = two 1's = "21" countAndSay(4) = say "21" = one 2 + one 1 = "12" + "11" = "1211"
Constraints:
1 <= n <= 30
Count and Say– LeetCode Solutions
class Solution { public: string countAndSay(int n) { string ans = "1"; while (--n) { string next; for (int i = 0; i < ans.length(); ++i) { int count = 1; while (i + 1 < ans.length() && ans[i] == ans[i + 1]) { ++count; ++i; } next += to_string(count) + ans[i]; } ans = move(next); } return ans; } };
class Solution { public String countAndSay(int n) { StringBuilder sb = new StringBuilder("1"); while (--n > 0) { StringBuilder next = new StringBuilder(); for (int i = 0; i < sb.length(); ++i) { int count = 1; while (i + 1 < sb.length() && sb.charAt(i) == sb.charAt(i + 1)) { ++count; ++i; } next.append(count).append(sb.charAt(i)); } sb = next; } return sb.toString(); } }
class Solution: def countAndSay(self, n: int) -> str: ans = '1' for _ in range(n - 1): nxt = '' i = 0 while i < len(ans): count = 1 while i + 1 < len(ans) and ans[i] == ans[i + 1]: count += 1 i += 1 nxt += str(count) + ans[i] i += 1 ans = nxt return ans
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