Day 10: Binary Numbers In Java | 30 Days Of Code | Hackerrank Programming Solutions

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Link for the ProblemDay 10: Binary Numbers – Hacker Rank Solution

Day 10: Binary Numbers – Hacker Rank Solution


Today, we’re working with binary numbers. Check out the Tutorial tab for learning materials and an instructional video!

Given a base- integer, , convert it to binary (base-). Then find and print the base- integer denoting the maximum number of consecutive ‘s in ‘s binary representation. When working with different bases, it is common to show the base as a subscript.


The binary representation of  is . In base , there are  and  consecutive ones in two groups. Print the maximum, .

Input Format

A single integer, .


Output Format

Print a single base- integer that denotes the maximum number of consecutive ‘s in the binary representation of .

Sample Input 1


Sample Output 1


Sample Input 2


Sample Output 2



Sample Case 1:
The binary representation of  is , so the maximum number of consecutive ‘s is .

Sample Case 2:
The binary representation of  is , so the maximum number of consecutive ‘s is .

Day 10: Binary Numbers – Hacker Rank Solution
import java.util.Scanner;

 * @author Techno-RJ
public class Day10BinaryNumbers {
	public static void main(String[] args) {
		Scanner in = new Scanner(;
		int n = in.nextInt();
		int r = n, counter = 0, maxOne = 0;
		String s = "";
		while (n > 0) {

			r = n % 2;
			if (r == 1) {
				if (counter > maxOne) {
					maxOne = counter;
			} else {
				counter = 0;
			s = r + s;
			n = n / 2;



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