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Link for the Problem – Day 16: Exceptions – String to Integerโ Hacker Rank Solution
Day 16: Exceptions - String to Integer โ Hacker Rank Solution
Problem:
Objective
Today, we’re getting started with Exceptions by learning how to parse an integer from a string and print a custom error message. Check out the Tutorial tab for learning materials and an instructional video!
Task
Read a string, , and print its integer value; if cannot be converted to an integer, print Bad String
.
Note: You must use the String-to-Integer and exception handling constructs built into your submission language. If you attempt to use loops/conditional statements, you will get a score.
Input Format
A single string, .
Constraints
- , where is the length of string .
- is composed of either lowercase letters () or decimal digits ().
Output Format
Print the parsed integer value of , or Bad String
if cannot be converted to an integer.
Sample Input 0
3
Sample Output 0
3
Sample Input 1
za
Sample Output 1
Bad String
Explanation
Sample Case contains an integer, so it should not raise an exception when we attempt to convert it to an integer. Thus, we print the .
Sample Case does not contain any integers, so an attempt to convert it to an integer will raise an exception. Thus, our exception handler prints Bad String
.
Day 16: Exceptions - String to Integer โ Hacker Rank Solution
import java.util.Scanner; /** * @author Techno-RJ * */ public class Day16ExceptionsStringToInteger { public static void main(String[] args) { Scanner in = new Scanner(System.in); String S = in.next(); in.close(); int i = 0; try { i = Integer.parseInt(S); System.out.println(i); } catch (NumberFormatException e) { System.out.println("Bad String"); } } }
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