# Day 19: Interfaces In Java | 30 Days Of Code | Hackerrank Programming Solutions

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Link for the ProblemDay 19: Interfaces – Hacker Rank Solution

`Day 19: Interfaces – Hacker Rank Solution`

### Problem:

Objective
Today, we’re learning about Interfaces. Check out the Tutorial tab for learning materials and an instructional video!

The `AdvancedArithmetic` interface and the method declaration for the abstract `divisorSum(n)` method are provided for you in the editor below.

Complete the implementation of `Calculator` class, which implements the `AdvancedArithmetic` interface. The implementation for the `divisorSum(n)` method must return the sum of all divisors of .

Example

The divisors of  are . Their sum is .

The divisors of  are  and their sum is .

Input Format

A single line with an integer, .

Constraints

Output Format

You are not responsible for printing anything to stdout. The locked template code in the editor below will call your code and print the necessary output.

Sample Input

```6
```

Sample Output

```I implemented: AdvancedArithmetic
12
```

Explanation

The integer  is evenly divisible by , , , and . Our divisorSum method should return the sum of these numbers, which is . The Solution class then prints  on the first line, followed by the sum returned by divisorSum (which is ) on the second line.

`Day 19: Interfaces – Hacker Rank Solution`
```import java.util.Scanner;

/**
* @author Techno-RJ
*
*/
int divisorSum(int n);
}
//renamed Calculator class to Calculator2 class as its already present in Day17 question

public int divisorSum(int n){
if(n==1)return 1;
int sum=1+n,r=0;
for(int i=2;i<n;i++){

r=n%i;
if(r==0){
sum=sum+i;
}
}
return sum;
}

}
public class Day19Interfaces {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int n = scan.nextInt();
scan.close(); 