Day 19: Interfaces In Java | 30 Days Of Code | Hackerrank Programming Solutions

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Link for the ProblemDay 19: Interfaces – Hacker Rank Solution

Day 19: Interfaces – Hacker Rank Solution


Today, we’re learning about Interfaces. Check out the Tutorial tab for learning materials and an instructional video!

The AdvancedArithmetic interface and the method declaration for the abstract divisorSum(n) method are provided for you in the editor below.

Complete the implementation of Calculator class, which implements the AdvancedArithmetic interface. The implementation for the divisorSum(n) method must return the sum of all divisors of .


The divisors of  are . Their sum is .

The divisors of  are  and their sum is .

Input Format

A single line with an integer, .


Output Format

You are not responsible for printing anything to stdout. The locked template code in the editor below will call your code and print the necessary output.

Sample Input


Sample Output

I implemented: AdvancedArithmetic


The integer  is evenly divisible by , , , and . Our divisorSum method should return the sum of these numbers, which is . The Solution class then prints  on the first line, followed by the sum returned by divisorSum (which is ) on the second line.

Day 19: Interfaces – Hacker Rank Solution
import java.util.Scanner;

 * @author Techno-RJ
interface AdvancedArithmetic{
	   int divisorSum(int n);
//renamed Calculator class to Calculator2 class as its already present in Day17 question
class Calculator2 implements AdvancedArithmetic{
    public int divisorSum(int n){
        if(n==1)return 1;
       int sum=1+n,r=0;
        for(int i=2;i<n;i++){
        return sum;
public class Day19Interfaces {
	 public static void main(String[] args) {
	        Scanner scan = new Scanner(;
	        int n = scan.nextInt();
	      	AdvancedArithmetic myCalculator = new Calculator2(); 
	        int sum = myCalculator.divisorSum(n);
	        System.out.println("I implemented: " + myCalculator.getClass().getInterfaces()[0].getName() );

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