Day 23: BST Level-Order Traversal In Java | 30 Days Of Code | Hackerrank Programming Solutions

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30 Days Of Code Hackerrank

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In this post, you will find the solution for Day 23: BST Level-Order Traversal in Java-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the Problem – Day 23: BST Level-Order Traversal – Hacker Rank Solution 

Day 23: BST Level-Order Traversal – Hacker Rank Solution

Problem: 

Day 23: BST Level-Order Traversal – Hacker Rank Solution
import java.util.LinkedList;
import java.util.Queue;
import java.util.Scanner;

/**
 * @author Techno-RJ
 *
 */
public class Day23BSTLevelOrderTraversal {
	static class Node {
		Node left, right;
		int data;

		Node(int data) {
			this.data = data;
			left = right = null;
		}
	}

	static void levelOrder(Node root) {
		if (root == null)
			System.out.println("nothing to display");
		Queue<Node> q = new LinkedList<Node>();
		q.add(root);
		while (!q.isEmpty()) {
			Node node = (Node) q.poll();
			System.out.print(node.data + " ");
			if (node.left != null)
				q.add(node.left);
			if (node.right != null)
				q.add(node.right);

		}
	}

	public static Node insert(Node root, int data) {
		if (root == null) {
			return new Node(data);
		} else {
			Node cur;
			if (data <= root.data) {
				cur = insert(root.left, data);
				root.left = cur;
			} else {
				cur = insert(root.right, data);
				root.right = cur;
			}
			return root;
		}
	}

	public static void main(String args[]) {
		Scanner sc = new Scanner(System.in);
		int T = sc.nextInt();
		Node root = null;
		while (T-- > 0) {
			int data = sc.nextInt();
			root = insert(root, data);
		}
		sc.close();
		levelOrder(root);
	}
}

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