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Link for the Problem – Day 26: Nested Logic – Hacker Rank Solution
Day 26: Nested Logic – Hacker Rank Solution
Problem:
Objective
Today’s challenge puts your understanding of nested conditional statements to the test. You already have the knowledge to complete this challenge, but check out the Tutorial tab for a video on testing.
Task
Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:
- If the book is returned on or before the expected return date, no fine will be charged (i.e.: .
- If the book is returned after the expected return day but still within the same calendar month and year as the expected return date, .
- If the book is returned after the expected return month but still within the same calendar year as the expected return date, the .
- If the book is returned after the calendar year in which it was expected, there is a fixed fine of .
Example
returned date
due date
The book is returned on time, so no fine is applied.
returned date
due date
The book is returned in the following year, so the fine is a fixed 10000.
Input Format
The first line contains space-separated integers denoting the respective , , and on which the book was actually returned.
The second line contains space-separated integers denoting the respective , , and on which the book was expected to be returned (due date).
Constraints
Output Format
Print a single integer denoting the library fine for the book received as input.
Sample Input
STDIN Function ----- -------- 9 6 2015 day = 9, month = 6, year = 2015 (date returned) 6 6 2015 day = 6, month = 6, year = 2015 (date due)
Sample Output
45
Explanation
Given the following return dates:
Returned:
Due:
Because , it is less than a year late.
Because , it is less than a month late.
Because , it was returned late (but still within the same month and year).
Per the library’s fee structure, we know that our fine will be . We then print the result of as our output.
Day 26: Nested Logic – Hacker Rank Solution
import java.util.Scanner; /** * @author Techno-RJ * */ public class Day26NestedLogic { public static void main(String[] args) { Scanner sc = new Scanner(System.in); String actualDate = sc.nextLine(); String expectedDate = sc.nextLine(); sc.close(); int fine = 0; String[] dateDetail = actualDate.split(" "); String[] eDetail = expectedDate.split(" "); int aDate = Integer.parseInt(dateDetail[0]); int aMonth = Integer.parseInt(dateDetail[1]); int ayear = Integer.parseInt(dateDetail[2]); int eDate = Integer.parseInt(eDetail[0]); int eMonth = Integer.parseInt(eDetail[1]); int eYear = Integer.parseInt(eDetail[2]); if (ayear > eYear) { fine = 10000; } else if (ayear == eYear && aMonth > eMonth) { fine = 500 * (aMonth - eMonth); } else if (ayear == eYear && aMonth == eMonth && aDate > eDate) { fine = 15 * (aDate - eDate); } System.out.println(fine); } }