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In this post, you will find the solution for **Find the Median** **in Java-HackerRank Problem**. We are providing the **correct and tested solutions** of coding problems present on **HackerRank**. If you are not able to solve any problem, then you can take help from our Blog/website.

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**Introduction To Algorithm**

The word **Algorithm** means “a process or set of rules to be followed in calculations or other problem-solving operations”. Therefore Algorithm refers to a set of rules/instructions that step-by-step define how a work is to be executed upon in order to get the expected results.

**Advantages of Algorithms:**

- It is easy to understand.
- Algorithm is a step-wise representation of a solution to a given problem.
- In Algorithm the problem is broken down into smaller pieces or steps hence, it is easier for the programmer to convert it into an actual program.

** Link for the Problem** – Find the Median – Hacker Rank Solution

Find the Median – Hacker Rank Solution

**Problem:**

The median of a list of numbers is essentially its middle element after sorting. The same number of elements occur after it as before. Given a list of numbers with an odd number of elements, find the median?

**Example**

The sorted array . The middle element and the median is .

**Function Description**

Complete the *findMedian* function in the editor below.

findMedian has the following parameter(s):

*int arr[n]:*an unsorted array of integers

**Returns**

*int:*the median of the array

**Input Format**

Find the Median – Hacker Rank Solution

import java.util.Arrays; import java.util.Scanner; /** * @author Techno-RJ * */ public class FindTheMedian { public static void main(String[] args) { /* * Enter your code here. Read input from STDIN. Print output to STDOUT. Your * class should be named Solution. */ Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int a[] = new int[n]; for (int i = 0; i < n; i++) a[i] = sc.nextInt(); Arrays.sort(a); if ((n & 1) == 1) { System.out.println(a[n / 2]); } else { System.out.println((a[n / 2] + a[n / 2 + 1]) / 2); } sc.close(); } }