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In this post, you will find the solution for the **House Robber** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – House Robber– LeetCode Problem

House Robber– LeetCode Problem

**Problem:**

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security systems connected and **it will automatically contact the police if two adjacent houses were broken into on the same night**.

Given an integer array `nums`

representing the amount of money of each house, return *the maximum amount of money you can rob tonight without alerting the police*.

**Example 1:**

Input:nums = [1,2,3,1]Output:4Explanation:Rob house 1 (money = 1) and then rob house 3 (money = 3). Total amount you can rob = 1 + 3 = 4.

**Example 2:**

Input:nums = [2,7,9,3,1]Output:12Explanation:Rob house 1 (money = 2), rob house 3 (money = 9) and rob house 5 (money = 1). Total amount you can rob = 2 + 9 + 1 = 12.

**Constraints:**

`1 <= nums.length <= 100`

`0 <= nums[i] <= 400`

House Robber– LeetCode Solutions

House RobberSolution in C++:

class Solution { public: int rob(vector<int>& nums) { int prev1 = 0; // dp[i - 1] int prev2 = 0; // dp[i - 2] for (const int num : nums) { const int dp = max(prev1, prev2 + num); prev2 = prev1; prev1 = dp; } return prev1; } };

House RobberSolution in Java:

class Solution { public int rob(int[] nums) { final int n = nums.length; if (n == 0) return 0; if (n == 1) return nums[0]; // dp[i] := max money of robbing nums[0..i] int[] dp = new int[n]; dp[0] = nums[0]; dp[1] = Math.max(nums[0], nums[1]); for (int i = 2; i < n; ++i) dp[i] = Math.max(dp[i - 1], dp[i - 2] + nums[i]); return dp[n - 1]; } }

House RobberSolution in Python:

class Solution: def rob(self, nums: List[int]) -> int: prev1 = 0 # dp[i - 1] prev2 = 0 # dp[i - 2] for num in nums: dp = max(prev1, prev2 + num) prev2 = prev1 prev1 = dp return prev1