Implement strStr() LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Link for the ProblemImplement strStr()– LeetCode Problem

Implement strStr()– LeetCode Problem

Problem:

Implement strStr().

Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.

Clarification:

What should we return when needle is an empty string? This is a great question to ask during an interview.

For the purpose of this problem, we will return 0 when needle is an empty string. This is consistent to C’s strstr() and Java’s indexOf().

Example 1:

Input: haystack = "hello", needle = "ll"
Output: 2

Example 2:

Input: haystack = "aaaaa", needle = "bba"
Output: -1

Example 3:

Input: haystack = "", needle = ""
Output: 0

Constraints:

  • 0 <= haystack.length, needle.length <= 5 * 104
  • haystack and needle consist of only lower-case English characters.
Implement strStr() – LeetCode Solutions
class Solution {
 public:
  int strStr(string haystack, string needle) {
    const int m = haystack.length();
    const int n = needle.length();

    for (int i = 0; i < m - n + 1; i++)
      if (haystack.substr(i, n) == needle)
        return i;

    return -1;
  }
};
class Solution {
  public int strStr(String haystack, String needle) {
    final int m = haystack.length();
    final int n = needle.length();

    for (int i = 0; i < m - n + 1; ++i)
      if (haystack.substring(i, i + n).equals(needle))
        return i;

    return -1;
  }
}
class Solution:
  def strStr(self, haystack: str, needle: str) -> int:
    m = len(haystack)
    n = len(needle)

    for i in range(m - n + 1):
      if haystack[i:i + n] == needle:
        return i

    return -1

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