Isomorphic Strings LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Isomorphic Strings in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the ProblemIsomorphic Strings– LeetCode Problem

Isomorphic Strings– LeetCode Problem


Given two strings s and tdetermine if they are isomorphic.

Two strings s and t are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character, but a character may map to itself.

Example 1:

Input: s = "egg", t = "add"
Output: true

Example 2:

Input: s = "foo", t = "bar"
Output: false

Example 3:

Input: s = "paper", t = "title"
Output: true


  • 1 <= s.length <= 5 * 104
  • t.length == s.length
  • s and t consist of any valid ASCII character.
Isomorphic Strings– LeetCode Solutions
Isomorphic Strings Solution in C++:
class Solution {
  bool isIsomorphic(string s, string t) {
    vector<int> charToIndex_s(128);
    vector<int> charToIndex_t(128);

    for (int i = 0; i < s.length(); ++i) {
      if (charToIndex_s[s[i]] != charToIndex_t[t[i]])
        return false;
      charToIndex_s[s[i]] = i + 1;
      charToIndex_t[t[i]] = i + 1;

    return true;
Isomorphic Strings Solution in Java:
class Solution {
  public boolean isIsomorphic(String s, String t) {
    Map<Character, Integer> charToIndex_s = new HashMap<>();
    Map<Character, Integer> charToIndex_t = new HashMap<>();

    for (Integer i = 0; i < s.length(); ++i)
      if (charToIndex_s.put(s.charAt(i), i) != charToIndex_t.put(t.charAt(i), i))
        return false;

    return true;
Isomorphic Strings Solution in Python:
class Solution:
  def isIsomorphic(self, s: str, t: str) -> bool:
    return [*map(s.index, s)] == [*map(t.index, t)]

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