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In this post, you will find the solution for Java 1D Array (Part 2) -HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.
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Introduction To Java
JAVA was developed by James Gosling at Sun Microsystems Inc in the year 1991, later acquired by Oracle Corporation. It is a simple programming language. Java makes writing, compiling, and debugging programming easy. It helps to create reusable code and modular programs.
Java is a class-based, object-oriented programming language and is designed to have as few implementation dependencies as possible. A general-purpose programming language made for developers to write once run anywhere that is compiled Java code can run on all platforms that support Java. Java applications are compiled to byte code that can run on any Java Virtual Machine. The syntax of Java is similar to c/c++.
Link for the Problem – Java 1D Array (Part 2) – Hacker Rank Solution
Java 1D Array (Part 2) – Hacker Rank Solution
Problem :
Let’s play a game on an array! You’re standing at index of an -element array named . From some index (where ), you can perform one of the following moves:
- Move Backward: If cell exists and contains a , you can walk back to cell .
Problem Statement: Click Here
Java 1D Array (Part 2) – Hacker Rank Solution
import java.util.*;
public class Solution {
public static boolean canWin(int leap, int[] game, int i) {
if (i < 0 || game[i] == 1)
return false;
if (i + 1 >= game.length || i + leap >= game.length)
return true;
game[i] = 1; //flag
return canWin(leap, game, i + leap)
|| canWin(leap, game, i + 1)
|| canWin(leap, game, i - 1);
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int q = scan.nextInt();
while (q-- > 0) {
int n = scan.nextInt();
int leap = scan.nextInt();
int[] game = new int[n];
for (int i = 0; i < n; i++) {
game[i] = scan.nextInt();
}
System.out.println((canWin(leap, game, 0)) ? "YES" : "NO");
}
scan.close();
}
}
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