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Link for the Problem – Java BitSet- Hacker Rank Solution

Java BitSet- Hacker Rank Solution

Problem :

Java’s BitSet class implements a vector of bit values (i.e.:  () or  ()) that grows as needed, allowing us to easily manipulate bits while optimizing space (when compared to other collections). Any element having a bit value of  is called a set bit.

Given  BitSets,  and , of size  where all bits in both BitSets are initialized to , perform a series of  operations. After each operation, print the number of set bits in the respective BitSets as two space-separated integers on a new line.

Problem Statement: Click Here.

Java BitSet- Hacker Rank Solution

import java.util.*;

class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int m = sc.nextInt();
        BitSet[] bits = {new BitSet(n), new BitSet(n)};

        for (int i = 0; i < m; i++) {
            String operation = sc.next();
            int x = sc.nextInt();
            int y = sc.nextInt();

            switch (operation) {
                case "AND":
                    bits[x - 1].and(bits[y - 1]);
                    break;
                case "OR":
                    bits[x - 1].or(bits[y - 1]);
                    break;
                case "XOR":
                    bits[x - 1].xor(bits[y - 1]);
                    break;
                case "FLIP":
                    bits[x - 1].flip(y);
                    break;
                case "SET":
                    bits[x - 1].set(y);
                    break;
                default:
                    break;
            }
            System.out.println(bits[0].cardinality() + " " + bits[1].cardinality());
        }
    }
}