Java Exception Handling | HackerRank Programming Solutions | HackerRank Java Solutions

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Link for the Problem – Java Exception Handling – Hacker Rank Solution

Java Exception Handling – Hacker Rank Solution

Objective

You are required to compute the power of a number by implementing a calculator. Create a class MyCalculator which consists of a single method long power(int, int). This method takes two integers, n and p, as parameters and finds . 

Problem Statement: Click Here

Java Exception Handling – Hacker Rank Solution

import java.util.*;
import java.util.Scanner;

class MyCalculator {
    long power(int n, int p) throws Exception {
        if (n < 0 || p < 0) {
            throw new Exception("n or p should not be negative.");
        } else if (n == 0 && p == 0) {
            throw new Exception("n and p should not be zero.");
        } else {
            return (long) Math.pow(n, p);
        }
    }
}

class Solution {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in .hasNextInt()) {
            int n = in .nextInt();
            int p = in .nextInt();
            MyCalculator my_calculator = new MyCalculator();
            try {
                System.out.println(my_calculator.power(n, p));
            } catch (Exception e) {
                System.out.println(e);
            }
        }
    }
}