Java Exception Handling Try-catch | HackerRank Programming Solutions | HackerRank Java Solutions

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JAVA was developed by James Gosling at Sun Microsystems Inc in the year 1991, later acquired by Oracle Corporation. It is a simple programming language. Java makes writing, compiling, and debugging programming easy. It helps to create reusable code and modular programs.

Java is a class-based, object-oriented programming language and is designed to have as few implementation dependencies as possible. A general-purpose programming language made for developers to write once run anywhere that is compiled Java code can run on all platforms that support Java. Java applications are compiled to byte code that can run on any Java Virtual Machine. The syntax of Java is similar to c/c++.

Link for the Problem – Java Exception Handling Try-catch – Hacker Rank Solution

Java Exception Handling Try-catch – Hacker Rank Solution

Objective

Exception handling is the process of responding to the occurrence, during computation, of exceptions – anomalous or exceptional conditions requiring special processing – often changing the normal flow of program execution.

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Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs.

This problem will test your knowledge on try-catch block.

You will be given two integers x and y as input, you have to compute x/y. If x and y are not 32 bit signed integers or if y is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.

Sample Input 0:

10
3

Sample Output 0:

3

Sample Input 1:

10
Hello

Sample Output 1:

java.util.InputMismatchException

Sample Input 2:

10
0

Sample Output 2:

java.lang.ArithmeticException: / by zero

Sample Input 3:

23.323
0

Sample Output 3:

java.util.InputMismatchException

Java Exception Handling Try-catch – Hacker Rank Solution

import java.util.Scanner;
class MyCalculator {
    long power(int n, int p) throws Exception {
        if (n < 0 || p < 0) {
            throw new Exception("n or p should not be negative.");
        } else if (n == 0 && p == 0) {
            throw new Exception("n and p should not be zero.");
        }
        return (long) Math.pow(n, p);
    }
}

public class Solution {
    public static final MyCalculator my_calculator = new MyCalculator();
    public static final Scanner in = new Scanner(System.in);
    
    public static void main(String[] args) {
        while (in .hasNextInt()) {
            int n = in .nextInt();
            int p = in .nextInt();
            
            try {
                System.out.println(my_calculator.power(n, p));
            } catch (Exception e) {
                System.out.println(e);
            }
        }
    }
}