Hello Programmers/Coders, Today we are going to share solutions of Programming problems of HackerRank of Programming Language Java . At Each Problem with Successful submission with all Test Cases Passed, you will get an score or marks. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.
In this post, you will find the solution for Java Interface-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.
Use “Ctrl+F” To Find Any Questions Answer. & For Mobile User, You Just Need To Click On Three dots In Your Browser & You Will Get A “Find” Option There. Use These Option to Get Any Random Questions Answer.
Introduction To Java
JAVA was developed by James Gosling at Sun Microsystems Inc in the year 1991, later acquired by Oracle Corporation. It is a simple programming language. Java makes writing, compiling, and debugging programming easy. It helps to create reusable code and modular programs.
Java is a class-based, object-oriented programming language and is designed to have as few implementation dependencies as possible. A general-purpose programming language made for developers to write once run anywhere that is compiled Java code can run on all platforms that support Java. Java applications are compiled to byte code that can run on any Java Virtual Machine. The syntax of Java is similar to c/c++.
Link for the Problem – Java Interface – Hacker Rank Solution
Java Interface – Hacker Rank Solution
Problem :
A Java interface can only contain method signatures and fields. The interface can be used to achieve polymorphism. In this problem, you will practice your knowledge on interfaces.
You are given an interface AdvancedArithmetic which contains a method signature int divisor_sum(int n). You need to write a class called MyCalculator which implements the interface.
divisorSum function just takes an integer as input and return the sum of all its divisors. For example divisors of 6 are 1, 2, 3 and 6, so divisor_sum should return 12. The value of n will be at most 1000.
Read the partially completed code in the editor and complete it. You just need to write the MyCalculator class only. Your class shouldn’t be public
Sample Input
6
Sample Output
I implemented: AdvancedArithmetic 12
Explanation
Divisors of 6 are 1,2,3 and 6. 1+2+3+6=12
Java Interface – Hacker Rank Solution
import java.util.*; interface AdvancedArithmetic{ int divisor_sum(int n); } //Write your code here class MyCalculator implements AdvancedArithmetic { public int divisor_sum(int n) { int sum=0; for(int i=1;i<=n;i++) { if(n%i==0) sum+=i; } return sum; } } class Solution{ public static void main(String []args){ MyCalculator my_calculator = new MyCalculator(); System.out.print("I implemented: "); ImplementedInterfaceNames(my_calculator); Scanner sc = new Scanner(System.in); int n = sc.nextInt(); System.out.print(my_calculator.divisor_sum(n) + "\n"); sc.close(); } /* * ImplementedInterfaceNames method takes an object and prints the name of the interfaces it implemented */ static void ImplementedInterfaceNames(Object o){ Class[] theInterfaces = o.getClass().getInterfaces(); for (int i = 0; i < theInterfaces.length; i++){ String interfaceName = theInterfaces[i].getName(); System.out.println(interfaceName); } } }
I have been surfing online greater than 3 hours today, yet I never discovered any interesting article like yours. It is lovely value sufficient for me. Personally, if all website owners and bloggers made just right content as you probably did, the net can be much more helpful than ever before.