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In this post, you will find the solution for Java Substring-HackerRank Problem. We are providing the correct and tested solutions of coding problems present on HackerRank. If you are not able to solve any problem, then you can take help from our Blog/website.
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Introduction To Java
JAVA was developed by James Gosling at Sun Microsystems Inc in the year 1991, later acquired by Oracle Corporation. It is a simple programming language. Java makes writing, compiling, and debugging programming easy. It helps to create reusable code and modular programs.
Java is a class-based, object-oriented programming language and is designed to have as few implementation dependencies as possible. A general-purpose programming language made for developers to write once run anywhere that is compiled Java code can run on all platforms that support Java. Java applications are compiled to byte code that can run on any Java Virtual Machine. The syntax of Java is similar to c/c++.
Link for the Problem – Java Substring – Hacker Rank Solution
Java Substring – Hacker Rank Solution
Problem :
Given a string,8 , and two indices, start and end, print a substring consisting of all characters in the inclusive range from start to end-1 . You’ll find the String class’ substring method helpful in completing this challenge.
Input Format
The first line contains a single string denoting 8.
The second line contains two space-separated integers denoting the respective values of start and end .
Constraints
- String consists of English alphabetic letters (i.e., ) only.
Output Format
Print the substring in the inclusive range from start to end-1 .
Sample Input
Helloworld 3 7
Sample Output
lowo
Explanation
In the diagram below, the substring is highlighted in green:
Java Substring – Hacker Rank Solution
import java.util.Scanner;
public class Solution {
public static void main(String[] args) {
/* Save input */
Scanner scan = new Scanner(System.in);
String A = scan.next();
String B = scan.next();
scan.close();
/* Sum lengths */
System.out.println(A.length() + B.length());
/* Compare lexicographical ordering */
System.out.println(A.compareTo(B) > 0 ? "Yes" : "No");
/* Print the Strings in desired format */
System.out.println(capFirstLetter(A) + " " + capFirstLetter(B));
}
private static String capFirstLetter(String str) {
if (str == null || str.length() == 0) {
return "";
} else {
return str.substring(0,1).toUpperCase() + str.substring(1);
}
}
}
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