Length of Last Word LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Length of Last Word in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the Problem – Length of Last Word– LeetCode Problem

Length of Last Word– LeetCode Problem

Problem:

Given a string s consisting of some words separated by some number of spaces, return the length of the last word in the string.

A word is a maximal substring consisting of non-space characters only.

Example 1:

Input: s = "Hello World"
Output: 5
Explanation: The last word is "World" with length 5.

Example 2:

Input: s = "   fly me   to   the moon  "
Output: 4
Explanation: The last word is "moon" with length 4.

Example 3:

Input: s = "luffy is still joyboy"
Output: 6
Explanation: The last word is "joyboy" with length 6.

Constraints:

• 1 <= s.length <= 104
• s consists of only English letters and spaces ' '.
• There will be at least one word in s

Length of Last Word– LeetCode Solutions

Length of Last Word in C++:

class Solution {
 public:
  int lengthOfLastWord(string s) {
    int i = s.length() - 1;

    while (i >= 0 && s[i] == ' ')
      --i;
    const int lastIndex = i;
    while (i >= 0 && s[i] != ' ')
      --i;

    return lastIndex - i;
  }
};

Length of Last Word in Java:

class Solution {
  public int lengthOfLastWord(String s) {
    int i = s.length() - 1;

    while (i >= 0 && s.charAt(i) == ' ')
      --i;
    final int lastIndex = i;
    while (i >= 0 && s.charAt(i) != ' ')
      --i;

    return lastIndex - i;
  }
}

Length of Last Word in Python:

class Solution:
  def lengthOfLastWord(self, s: str) -> int:
    i = len(s) - 1

    while i >= 0 and s[i] == ' ':
      i -= 1
    lastIndex = i
    while i >= 0 and s[i] != ' ':
      i -= 1

    return lastIndex - i