Maximum Subarray LeetCode Programming Solutions | LeetCode Problem Solutions in C++, Java, & Python [💯Correct]

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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Maximum Subarray in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the Problem – Maximum Subarray – LeetCode Problem

Maximum Subarray – LeetCode Problem

Problem:

Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.

A subarray is a contiguous part of an array.

Example 1:

Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.

Example 2:

Input: nums = [1]
Output: 1

Example 3:

Input: nums = [5,4,-1,7,8]
Output: 23

Constraints:

• 1 <= nums.length <= 105
• -104 <= nums[i] <= 104

Maximum Subarray– LeetCode Solutions

Maximum Subarray in C++:

class Solution {
 public:
  int maxSubArray(vector<int>& nums) {
    int ans = INT_MIN;
    int sum = 0;

    for (const int num : nums) {
      sum += num;
      ans = max(ans, sum);
      sum = max(sum, 0);
    }

    return ans;
  }
};

Maximum Subarray in Java:

class Solution {
  public int maxSubArray(int[] nums) {
    int ans = Integer.MIN_VALUE;
    int sum = 0;

    for (final int num : nums) {
      sum += num;
      ans = Math.max(ans, sum);
      sum = Math.max(sum, 0);
    }

    return ans;
  }
}

Maximum Subarray in Python:

class Solution:
  def maxSubArray(self, nums: List[int]) -> int:
    ans = -inf
    summ = 0

    for num in nums:
      summ += num
      ans = max(ans, summ)
      summ = max(summ, 0)

    return ans